根據加入從不同表中選擇記錄數

Question

我想要獲取用戶在不同表中輸入的記錄數。 DB的模式是：

+-----------------------+ 
| Survey Master   | 
+----------------+------+ 
| Field   | Key | 
+----------------+------+ 
| id    | PK | 
| Username  |  | 
| FamilyMasterId | FK | 
+----------------+------+ 

+------------+------+ 
| Family Master  | 
+------------+------+ 
| Field  | Key | 
+------------+------+ 
| id   | PK | 
+------------+------+ 

+-----------------------+ 
| Family Detail   | 
+----------------+------+ 
| Field   | Key | 
+----------------+------+ 
| id    | PK | 
| FamilyMasterId | FK | 
+----------------+------+ 

+-----------------------+ 
| Travel Master   | 
+----------------+------+ 
| Field   | Key | 
+----------------+------+ 
| id    | PK | 
| FamilyDetailId | FK | 
+----------------+------+ 

+-----------------------+ 
| Travel Detail   | 
+----------------+------+ 
| Field   | Key | 
+----------------+------+ 
| id    | PK | 
| TravelMasterId | FK | 
+----------------+------+ 

我希望看到每個用戶在每個表是這樣創造的記錄數：

：

Username SurveyMaster FamilyMaster FamilyDetail TravelMaster TravelDetail 
---------- -------------- -------------- -------------- -------------- -------------- 
    User001 59    47    36    26    12    
    User002 88    76    64    42    25    
    User003 49    44    35    25    15    
    User004 77    69    55    45    37 

查看以下鏈接後

1. Find Records from Different Tables
2. Select count(*) from multiple tables
3. http://www.sqlines.com/mysql/how-to/join-different-tables-based-on-condition
4. http://www.informit.com/articles/article.aspx?p=30875&seqNum=5
5. SQL: Combine Select count(*) from multiple tables

我能寫這個查詢，但它給出了相同的記錄中的所有列：

SELECT USERNAME, COUNT(USERNAME) SURVEYMASTER, COUNT(USERNAME) FAMILYMASTER, COUNT(USERNAME) FAMILYDETAIL, COUNT(USERNAME) TRAVELMASTER, COUNT(USERNAME) TRAVELDETAIL FROM 
((SELECT CREATEUSER USERNAME FROM SURVEYMASTER 
) 
UNION ALL 
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM 
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID 
) 
UNION ALL 
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM 
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID 
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID 
) 
UNION ALL 
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM 
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID 
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID 
INNER JOIN TRAVELMASTER TM ON FD.ID = TM.FAMILYDETAILID 
) 
UNION ALL 
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM 
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID 
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID 
INNER JOIN TRAVELMASTER TM ON FD.ID = TM.FAMILYDETAILID 
INNER JOIN TRAVELDETAIL TD ON TM.ID = TD.TRAVELMASTERID 
) 
) T 
GROUP BY USERNAME 
ORDER BY USERNAME 

編輯

這裏是關係描述：

1. FamilyMasterId是SurveyMaster和FamilyDetail 表中的外鍵。
2. FamilyDetailId是TravelMaster表中的外鍵。
3. TravelMasterId是TravelDetail表中的外鍵。

Answer 1

這可能不是完美的解決方案，如果我們考慮性能，但它可以得到期望的結果

SELECT sm.Username , 
     COUNT(*) SurveyMaster , 
     COUNT(FamilyMasterId) FamilyMaster , 
     fd.FamilyDetail , 
     tm.TravelMaster , 
     td.TravelDetail 
FROM SurveyMaster sm 
     JOIN (SELECT Username , 
         COUNT(fd.id) FamilyDetail 
       FROM  SurveyMaster sm 
         JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id 
         JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId 
       GROUP BY Username 
      ) fd ON sm.Username = fd.Username 
     JOIN (SELECT Username , 
         COUNT(tm.id) TravelMaster 
       FROM  SurveyMaster sm 
         JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id 
         JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId 
         JOIN TravelMaster tm ON fd.Id = tm.FamilyDetailId 
       GROUP BY Username 
      ) tm ON sm.Username = tm.Username 
     JOIN (SELECT Username , 
         COUNT(td.id) TravelDetail 
       FROM  SurveyMaster sm 
         JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id 
         JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId 
         JOIN TravelMaster tm ON fd.Id = tm.FamilyDetailId 
         JOIN TravelDetail td ON tm.Id = td.TravelMasterId 
       GROUP BY Username 
      ) td ON sm.Username = td.Username 
GROUP BY sm.Username , 
     fd.FamilyDetail , 
     tm.TravelMaster , 
     td.TravelDetail;