的Grails的白水

Question

域級別執行我有三個領域類

class Caller implements Serializable{ 
    String callingNumber 
    String callerName 
    static hasMany = [ callCallerList : CallCallerList ] 
} 

而其他都

class CallCallerList { 
    String reason 
    Caller caller 
    CallerList callerList 
} 
class CallerList { 

    String name 

} 

來電

和

CallerList

有一對多的關係與

CallCallerList

我在那裏我閱讀完所有的來電者，並把他們進入callCallerList巨大的csv文件。

def callerList = new CallerList(name:'test') 
    def callCallerLists = [] 
    callerList.save(flush:true) 
    groovyFile.each { 
      ArrayList<String> line = it.split(',').toList() 
      def caller = new Caller(callingNumber:line.get(0),callerName:line.get(1)) 
//I want to save the object latter when I run the saveAll function for this domain class. 
def callCallerList = new CallCallerList(caller:caller,callerList:callerList,reason:line.get(2)) 
    callCallerLists.add(callCallerList) 
// this gives me the error that caller is unsaved object. 
} 
CallCallerList.saveAll(callCallerLists) 

我不希望保存來電，因爲我的進程得到緩慢的，如果數以百萬計的文件，如果記錄，同時創造大量callCallerList然後所有來電者保存，但不能以任何callerList出現一些錯誤。 我想這樣做

Caller.saveAll(callers) 
CallCallerList(callCallerLists) 

Answer 1

我已經做到了這一點，並解決了上述問題。

def callerList = new CallerList(name:'test') 
    def callCallerLists = [] 
    def callers = [] 
    callerList.save(flush:true) 
    groovyFile.each { 
      ArrayList<String> line = it.split(',').toList() 
      def caller = new Caller(callingNumber:line.get(0),callerName:line.get(1)) 
//I want to save the object latter when I run the saveAll function for this domain class. 
def callCallerList = new CallCallerList(callerList:callerList,reason:line.get(2)) 
    callers.add(caller) 
    callCallerLists.add(callCallerList) 
// this gives me the error that caller is unsaved object. 
} 
Caller.saveAll(callers) 
for(int i =0;i< callCallerLists?.size();i++){ 
        callCallerLists?.get(i)?.caller = callers?.get(i) 
       } 
CallCallerList.saveAll(callCallerLists)