在SQL Server Express 2005中自動重建索引

Question

我的團隊正在研究.NET Web應用程序，其數據存儲通過SQL Server 2005 Express進行管理。是否可以自動執行數據庫中的任務，以便在部署/安裝後按間隔自動重建特定索引？如果是這樣，這是如何實現的？我認爲這將在數據庫的tasks下，但我沒有看到它。

Answer 1

當我服務我的數據庫時，此腳本幫助我刪除索引的碎片。也許，它對你有用：

SET NOCOUNT ON; 

DECLARE 
     @SQL NVARCHAR(MAX) 
    , @IndexName SYSNAME 
    , @Output VARCHAR(200) 
    , @ServerVersion VARCHAR(100) 

SELECT @ServerVersion = CAST(SERVERPROPERTY('Edition') AS VARCHAR(100)) 

DECLARE cur CURSOR LOCAL READ_ONLY FORWARD_ONLY FOR 
    SELECT 
     'ALTER INDEX [' + ix.name + N'] ON [' + SCHEMA_NAME(t.[schema_id]) + '].[' + t.name + '] ' + 
     CASE 
      WHEN ps.avg_fragmentation_in_percent > 50 THEN 
       CASE WHEN @ServerVersion LIKE 'Enterprise%' OR @ServerVersion LIKE 'Developer%' THEN 
        'REBUILD WITH (SORT_IN_TEMPDB = ON, ONLINE = ON ' + CASE WHEN ix.fill_factor > 0 THEN ', FILLFACTOR = ' + CAST(ix.fill_factor AS VARCHAR(3)) ELSE '' END + ') ' 
       ELSE 
        'REBUILD WITH (SORT_IN_TEMPDB = ON' + CASE WHEN ix.fill_factor > 0 THEN ', FILLFACTOR = ' + CAST(ix.fill_factor AS VARCHAR(3)) ELSE '' END + ') ' 
      END 
      ELSE 'REORGANIZE ' 
     END + 
     CASE 
      WHEN ps.partition_number > 1 THEN N' PARTITION = ' + CAST(ps.partition_number AS NVARCHAR(MAX)) 
      ELSE N'' 
     END + ';', ix.name 
    FROM sys.indexes ix 
    JOIN sys.objects t ON t.[object_id] = ix.[object_id] 
    JOIN (
     SELECT 
       [object_id] 
      , index_id 
      , avg_fragmentation_in_percent 
      , partition_number 
     FROM sys.dm_db_index_physical_stats(DB_ID(), NULL, NULL, NULL, N'LIMITED') 
     WHERE page_count > 100 
      AND avg_fragmentation_in_percent > 10 
    ) ps ON t.[object_id] = ps.[object_id] AND ix.index_id = ps.index_id 

OPEN cur 

FETCH NEXT FROM cur INTO @SQL, @IndexName 

WHILE @@FETCH_STATUS = 0 BEGIN 

    SELECT @Output = CONVERT(NVARCHAR(15), GETDATE(), 114) + ': ' + @IndexName 
    RAISERROR(@Output, 0, 1) WITH NOWAIT 

    EXEC (@SQL) 

    FETCH NEXT FROM cur INTO @SQL, @IndexName 

END 

CLOSE cur 
DEALLOCATE cur