我的PHP是這樣的:綁定多個參數
$sql1="SELECT @rownum := @rownum + 1 Rank, q.* FROM (SELECT @rownum:=0) r,(SELECT * ,sum(`number of cases`) as tot, sum(`number of cases`) * 100/t.s AS `% of total` FROM `myTable` CROSS JOIN (SELECT SUM(`number of cases`) AS s FROM `myTable` where `type`=:criteria and `condition`=:diagnosis) t where `type`=:criteria and `condition`=:diagnosis group by `name` order by `% of total` desc) q"";
$stmt = $dbh->prepare($sql1);
$stmt->bindParam(':criteria', $search_crit, PDO::PARAM_STR);
$stmt->bindParam(':diagnosis', $diagnosis, PDO::PARAM_STR);
$stmt->execute();
$result1 = $stmt->fetchAll(PDO::FETCH_ASSOC);
header('Content-type: application/json');
echo json_encode($result1);
我在這條線得到一個錯誤:$stmt->execute();
錯誤說:
PHP Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[HY093]: Invalid parameter number' in php/rankings.php:39
堆棧跟蹤:
"#"0 php/rankings.php(39): PDOStatement->execute()
"#"1 {main} thrown in php/rankings.php on line 39
我該如何解決這個問題?我知道我可以通過一個準備好的聲明傳遞多個變量,但我不太確定如何去做。
請告訴我們您的** **完全錯誤消息,其你得到並確保你向我們展示你的**真實**和正確的代碼。 – Rizier123
你確定'$ search_crit'和'$ diagnosis'的內容嗎? – Random
@Random是的...只是'var_dump'和值是正確的。 – jonmrich