SQL當結果有兩行輸出時，我該如何求和它們？

Question

下面我有此查詢：

Select 
count(CDT) as Actions 
From Player_Tapjoy 
Where 
Trunc(CDT) >= To_Date('2012-sep-01','yyyy-mon-dd') 
And Trunc(CDT) < To_Date('2012-sep-12','yyyy-mon-dd') 
Union All 
Select 
Count(CDT) As Actions 
From Player_aux_pt 
Where 
Site = 'AppCircle' And 
Trunc(CDT) >= To_Date('2012-sep-01','yyyy-mon-dd') 
And Trunc(CDT) < To_Date('2012-sep-12','yyyy-mon-dd') 

這個輸出給了我兩行，每一個的選擇功能。我怎樣才能組合這些來獲得兩個選擇功能的總和？最重要的是，我如何按CDT（日期）對它進行分組？

Answer 1

我想你按日期查找這樣的事情，與分組：

select cdt, sum(actions) as actions_sum 
    from ( select trunc(cdt) as cdt, count(cdt) as actions 
       from player_tapjoy 
      where trunc(cdt) >= to_date('2012-sep-01', 'yyyy-mon-dd') and 
        trunc(cdt) < to_date('2012-sep-12', 'yyyy-mon-dd') 
      group by trunc(cdt) 
      union all 
      select trunc(cdt) as cdt, count(cdt) as actions 
       from player_aux_pt 
      where site = 'AppCircle' and 
        trunc(cdt) >= to_date('2012-sep-01', 'yyyy-mon-dd') and 
        trunc(cdt) < to_date('2012-sep-12', 'yyyy-mon-dd') 
      group by trunc(cdt)) 
group by cdt