我該如何將這個結果集合起來讓父母和孩子都成爲一個層次？

我正在試圖壓扁這個數組，使得這個孩子與父親的水平相同。我試過了其他StackOverflow問題的解決方案，如this和this，但無濟於事。有任何想法嗎？我該如何將這個結果集合起來讓父母和孩子都成爲一個層次？

(int) 3 => object() { 

    "new" => false, 
    "properties" => [ 
     "id" => (int) 180, 
     "name" => "Herp de Derp", 
     "parent_id" => (int) 169, 
     "lft" => (int) 16, 
     "rght" => (int) 19, 
     "children" => [ 
      (int) 0 => object(App\Model\Entity\Team) { 

       "new" => false, 
       "properties" => [ 
        "id" => (int) 188, 
        "name" => "dood dood", 
        "parent_id" => (int) 180, 
        "lft" => (int) 17, 
        "rght" => (int) 18, 
        "children" => [] 
       ], 
       "repository" => "Teams" 
      } 
     ] 
    ], 
    "repository" => "Teams" 
},

這應該適用於孫輩，孫輩等，不僅僅是父母和小孩。

來源

2014-09-26 Isaac Askew

你看着陣的問題，但你的數據是一個對象，你嘗試轉換爲數組，然後在它 – Dale 2014-09-26 18:18:34

呀我正在運行的其他想法m運行'toArray'（CakePHP 3命令），它應該已經轉換了它，所以我認爲調試只是轉換前的對象表示。我會盡量快速確認。 – 2014-09-26 18:23:51

最後，如果你想從一個不知名的扁平化下來樹深度，你需要遞歸。我嘲笑你的樣本對象的一個稍微更廣泛的例子在一個文件中（「test.json」）：

{ 
    "new": false, 
    "properties": { 
     "children": [ 
      { 
       "new": false, 
       "properties": { 
        "children": [], 
        "id": 188, 
        "lft": 17, 
        "name": "dood dood", 
        "parent_id": 180, 
        "rght": 18 
       }, 
       "repository": "Teams" 
      }, 
      { 
       "new": false, 
       "properties": { 
        "children": [], 
        "id": 182 
       }, 
       "repository": "Teams" 
      } 
     ], 
     "id": 180, 
     "lft": 16, 
     "name": "Herp de Derp", 
     "parent_id": 169, 
     "rght": 19 
    }, 
    "repository": "Teams" 
}

我在PHP創建通過此列舉的一個例子程序如下圖所示：

<?php 
// $x is the JSON representation of this object (quick for scaffolding purposes) 
// $y is the object representation 
$x = file_get_contents("test.json"); 
$y = json_decode($x); 

// $memo is our final product, an array that is written to as we traverse the object's children 
$memo = []; 

// Using recursive closure to walk the object/children and append to $memo 
$z = function($n) use (&$z, &$memo) { 
    // Build clone $o (sans children) of $n: 
    $o = new stdClass; 
    $o->new = $n->new; 
    $o->repository = $n->repository; 
    $o->properties = []; 

    $children = []; 
    foreach($n->properties as $k => $v) { 
     if($k == "children") { 
      // Do children afterward, to ensure current object 
      // appears in array before children 
      $children = $v; 
      continue; 
     } else { 
      $o->properties[$k] = $v; 
     } 
    } 
    array_push($memo, $o); 
    array_walk($children, $z); 
}; 
$z($y); 
print_r($memo);

$z是我的遞歸函數，我選擇將它作爲優先級的閉包實現。我首先分配一個空數組（$memo），然後通過首先添加當前對象來填充，然後在事實之後添加對象的子對象。當它遍歷子元素時，遞歸函數會自動爲其子元素調用，如有必要，等等。

通過上述，我的輸出表現爲：

Array 
(
    [0] => stdClass Object 
     (
      [new] => 
      [repository] => Teams 
      [properties] => Array 
       (
        [id] => 180 
        [name] => Herp de Derp 
        [parent_id] => 169 
        [lft] => 16 
        [rght] => 19 
       ) 

     ) 

    [1] => stdClass Object 
     (
      [new] => 
      [repository] => Teams 
      [properties] => Array 
       (
        [id] => 188 
        [name] => dood dood 
        [parent_id] => 180 
        [lft] => 17 
        [rght] => 18 
       ) 

     ) 

    [2] => stdClass Object 
     (
      [new] => 
      [repository] => Teams 
      [properties] => Array 
       (
        [id] => 182 
       ) 

     ) 

)

來源

2014-09-26 20:55:11

你需要的是一個對象轉換爲數組：

$arr = (array) $obj;

對JSON對象使用json_decode：

$arr = json_decode(json_encode($obj), true);

來源

2014-09-26 18:27:22

我該如何將這個結果集合起來讓父母和孩子都成爲一個層次？

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