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端口9070是簡單的HTTP服務器(無ZMQ TCP)
我有一個問題:爲什麼zmq_stream客戶端需要recv四次才能獲取實際數據?
- 爲什麼第二recv的是0?它來自哪裏?
感謝您的幫助
void test_stream_to_tcp()
{
uint8_t id [256];
size_t id_size = 256;
uint8_t buffer [256];
void *ctx = zmq_ctx_new();
void *client = zmq_socket (ctx, ZMQ_STREAM);
int rc = 0;
rc = zmq_connect (client, "tcp://localhost:9070");
rc = zmq_getsockopt (client, ZMQ_IDENTITY, id, &id_size);
rc = zmq_send (client, id, id_size, ZMQ_SNDMORE);
rc = zmq_send (client, "GET /\n\n", 7, 0);
assert (rc == 7);
rc = zmq_recv (client, buffer, 256, 0);
cout <<"first recv "<< buffer << "rc = "<< rc<<endl;
rc = zmq_recv (client, buffer, 256, 0);
cout <<"second recv "<< buffer<< "rc = "<< rc<<endl;
rc = zmq_recv (client, buffer, 256, 0);
cout <<"third recv "<< buffer<< "rc = "<< rc<<endl;
rc = zmq_recv (client, buffer, 256, 0);
buffer[rc] = '\0';
cout <<"forth recv "<< buffer<< "rc = "<< rc<<endl;
}
我意識到這是一個古老的答案。我有同樣的問題。我發送數據到這個客戶端,但接收5個字節,0個字節,5個字節,然後是真正的消息。誰需要發送0長度的消息? – CptanPanic