如何在android中解析jsonArray？

Question

我得到了一個JSON，我試圖根據值解析和排序分數。我甚至無法解析它。以下是我的JSON響應。

[ 
     {"scores": 
     { "a":1.460211E-17, 
      "b":3.808661E-20, 
      "c":3.07329371E-14, 
      "d":1.02141569E-17, 
      "e":1, 
      "f":6.26432543E-12, 
      "g":3.75437664E-14, 
      "h":1.877707E-21 
     }, 
     "rectangle": 
     { "left":142, 
     "width":882, 
     "top":0, 
     "height":848 
     } 
    } 
    ] 

我試圖將字符串轉換爲JSONObject，但錯誤表示它是JSONArray。

JSONObject reader = new JSONObject(json); 
JSONArray jsonArray = reader.optJSONArray("scores"); 

像

org.json.JSONException: Value of type org.json.JSONArray cannot be converted to JSONObject 

得到錯誤，所以我認爲值已經是一個JSON陣列。我想下面的代碼...

JSONArray jsonArray = reader.optJSONArray("scores"); 

和

JSONArray cast = jsonResponse.getJSONArray("scores"); 

...但它引發以下錯誤：

cannot resolve method optJSONArray()java.lang.String) 
cannot resolve method getJSONArray()java.lang.String) 

Answer 1

你的錯誤org.json.JSONException: Value of type org.json.JSONArray cannot be converted to JSONObject清楚地說，你正在嘗試將JSONArray解析爲JSONObject

做到這一點

JSONArray reader = new JSONArray(json); 
JSONObject jsonArray = reader.getJSONObject(0).optJSONObject("scores"); // replace 0 with your own index 

Answer 2

試試這個如果，例如，你從一個HTTP請求獲取的JSON：

HttpPost httppost = new HttpPost("http://www.somepage.php"); 

HttpParams mHttpParams = new BasicHttpParams(); 
HttpConnectionParams.setConnectionTimeout(mHttpParams, myConnectionTimeOut); 
HttpConnectionParams.setSoTimeout(mHttpParams, myTimeOut); 

HttpClient httpclient = new DefaultHttpClient(mHttpParams); 
HttpResponse response = httpclient.execute(httppost); 
HttpEntity entity = response.getEntity(); 
BufferedReader rd = new BufferedReader(new InputStreamReader(entity.getContent())); 
StringBuilder sb = new StringBuilder(); 

String line = null; 
while ((line = rd.readLine()) != null) { 
    sb.append(line ); 
} 

JSONArray jsonArray = json.getJSONArray("scores"); 

for(int i = 0; i < jsonArray .length(); i++) { 
    /* Do what you want here*/               
} 

希望它可以幫助

Answer 3

try { 
     JSONArray array= new JSONArray("your string"); 

     JSONObject object= array.getJSONObject(0); 
     JSONObject 
     scores=object.getJSONObject("scores"); 
     String [] subjects={"a","b","c","d","e","f","g","h"}; 
     for(int i=0;i<subjects.length;i++){ 

      Log.e("TAG",scores.getString(subjects[i])); 

     } 
    } catch (JSONException e) { 
     e.printStackTrace(); 
    }