如果你真的想從數據庫加載值和用戶檢查特定的值,那麼你可以使用二進制搜索一個簡單的例子,否則你也可以使用SQL查詢。
下面是一個實現(二進制搜索)來查找數組中的值。
public class BinarySearch {
public static void main(String[] a) {
int[] numArray = {5,6,10,11,19,18,30,25,88,44,55,1,3};
Arrays.sort(numArray);
// performing a binary search - here 100 is the element that you want
// to search in your array
System.out.println(searchElement(numArray, 100));
}
private static int searchElement(int[] sortedArray, int element) {
int first = 0;
int upto = sortedArray.length;
while (first < upto) {
int mid = (first + upto)/2; // Compute mid point.
if (element < sortedArray[mid]) {
upto = mid; // repeat search in bottom half.
} else if (element > sortedArray[mid]) {
first = mid + 1; // Repeat search in top half.
} else {
return sortedArray[mid]; // Found it. You can return the position or the element
}
}
return -1; // The element is not in the array
}
}
的數據庫功能
public class RetrieveValues {
public static void main(String args[]) throws SQLException {
Connection conn = null;
Statement select = null;
try {
Class.forName("com.somejdbcvendor.TheirJdbcDriver");
conn = DriverManager.getConnection(
"jdbc:somejdbcvendor:other data needed by some jdbc vendor",
"myLogin", "myPassword");
select = conn.createStatement();
ResultSet result = select
.executeQuery("SELECT Element FROM TestTable");
List<Integer> elementList = new ArrayList<Integer>();
while (result.next()) { // process results one row at a time
elementList.add(result.getInt(1));
}
// convert to int array
convertIntegers(elementList);
} catch (SQLException e) {
e.printStackTrace();
} catch (ClassNotFoundException e) {
e.printStackTrace();
} finally {
select.close();
conn.close();
}
}
public static int[] convertIntegers(List<Integer> elemIntegers)
{
int[] elements = new int[elemIntegers.size()];
for (int i=0; i < elements.length; i++)
{
elements[i] = elemIntegers.get(i).intValue();
}
return elements;
}
}
谷歌 - Access數據庫JDBC。 – 2012-08-10 14:57:48
@BheshGurung我明白如何連接和獲取數據到一個結果集,我只是不知道如何得到這個解析到一個數組 – AceFire6 2012-08-10 15:23:36