無法將類型的價值「的NSMutableArray」預期參數類型「[SKTexture]」

Question

我得到下面的代碼中的錯誤：

func prepareAnimationForDictionary(settings: NSDictionary,repeated: Bool) -> SKAction { 
     let atlas: SKTextureAtlas = 
      SKTextureAtlas(named: settings["AtlasFileName"] as! String) 
     let textureNames:NSArray = settings["Frames"] as! NSArray 
     let texturePack: NSMutableArray = [] 

     for texPath in textureNames { 
      texturePack.addObject(atlas.textureNamed(texPath as! String)) 
     } 

     let timePerFrame: NSTimeInterval = Double(1.0/(settings["FPS"] 
     as! Float)) 

     let anim:SKAction = SKAction.animateWithTextures(texturePack, 
      timePerFrame: timePerFrame) // the error I get is here 
     if repeated { 
     return SKAction.repeatActionForever(anim) 
     }else{ 
     return anim 
     } 

Answer 1

變化timePerFrame 到(timePerFrame as [AnyObject]) as! [SKTexture]

Answer 2

只需使用預期（斯威夫特）類型

... 
let textureNames = settings["Frames"] as! [String] 
var texturePack = [SKTexture]() 

for texPath in textureNames { 
    texturePack.append(atlas.textureNamed(texPath)) 
} 
... 

但從雨燕點可變基金會收藏類型NSMutableArray和NSMutableDictionary是未指定的類型，與Swift本地對應方無關。

Answer 3

好的，想想這個。你有一個變量texturePack。您不顯示聲明，但基於錯誤消息，我將假定它是NSMutableArray類型。有問題的電話需要一組SKTexture對象。

所以，投你texturePack到所需的類型：

let anim:SKAction = SKAction.animateWithTextures(texturePack as! [SKTexture], 
    timePerFrame: timePerFrame) //error i get is here 

注意，如果有任何機會，texturePack不是SKTexture對象的數組，你會使用if let或guard檢查會更好轉換成功：

guard 
    let anim:SKAction = SKAction.animateWithTextures(texturePack as! [SKTexture], 
    timePerFrame: timePerFrame) //error i get is here 
else 
{ 
    return nil; 
} 

或者，正如其他人所說，改變你的texturePack數組的聲明爲類型[SKTexture]