程序每次運行一行

Question

我對編程有點新，並且無法確定整個代碼爲什麼一次運行。我如何製作它，以便一次向用戶提供一件事？我確定這件事很簡單，但我一定已經忘記了。謝謝。

#include<iostream> 
using namespace std; 

int main() 
{ 

    int length; 
    int width; 
    int height; 
    int numberCoats; 
    int squareFeet; 
    int name; 
    int paintNeeded; 
    int brushesNeeded; 
    int coatsPaint; 
    int gallonsPaint; 

    cout << "Welcome to the program! What is your first name? \n"; 
    cin >> name; 


    cout << name << " What is the length of the house?"; 
    cin >> length; 


    cout << name << " What is the width of the house?"; 
    cin >> width; 


    cout << name << " What is the height of the house?"; 
    cin >> height; 

    cout << name << " How many coats of paint will it need?"; 
    cin >> coatsPaint; 


    squareFeet = length * width * height; 
    paintNeeded = squareFeet/325; 
    brushesNeeded = squareFeet/1100; 
    gallonsPaint = coatsPaint * paintNeeded; 

    cout << name << " , the amount of square feet is " << squareFeet << endl; 
    cout << name << " , the amount of coats of paint you will need is " << coatsPaint << endl; 
    cout << name << " , you will need " << gallonsPaint << " of paint" << endl; 
    cout << name << " , you will need " << brushesNeeded << " of brushes" << endl; 

        system("pause"); 
        return 0; 
} 

Answer 1

當你進入（例如）Chad您的姓名，該cin >> name將失敗因爲name是不可或缺的類型，而不是一個字符串類型。

這意味着Chad將留在輸入流中，所有其他cin >> xx語句也將失敗（因爲它們也是整型）。

如果你要輸入您的姓名作爲7，你會發現它工作得很好，除了這不是你的名字:-)

一個更好的解決辦法是改變name成std::string和使用的事實getline()閱讀它：

#include <string> 

std::string name; 

getline(cin, name); 

使用getline()的原因而不是cin >>是因爲後者將停在白色空間，而前者將獲得整條生產線。

換句話說，輸入Chad Morgan仍然存在您目前所看到的問題，因爲它會接受Chad作爲您的名字，並嘗試將Morgan作爲您家的長度。