我想輸入一個io::stdio
實例和一個BufReader
包裝文件,以便我可以編寫假設緩衝輸入源的代碼。我試過的嘗試投放的io::stdio()
到BufRead
類型的若干變化和所有已經失敗的一個或多個變化:在io :: stdio和BufReader之間強制BufRead特性兼容性
error: mismatched types:
expected `std::io::stdio::StdinLock<'_>`,
found `std::io::buffered::BufReader<std::fs::File>`
(expected struct `std::io::stdio::StdinLock`,
found struct `std::io::buffered::BufReader`) [E0308]
csv_to_json.rs:26 reader = BufReader::new(file.unwrap());
下面的代碼:我已經試過
use std::io;
use std::io::BufReader;
use std::io::prelude::*;
use std::env;
use std::process::exit;
use std::fs::File;
fn usage() {
println!("Usage: cat input.csv | csv_to_json");
}
fn main() {
let stdin = io::stdin();
let mut reader = stdin.lock(); // Assignment. (1)
let args: Vec<String> = env::args().collect();
if args.len() > 1 {
usage();
exit(1);
} else if args.len() == 1 {
let file = File::open(args[0].clone());
if !file.is_ok() {
usage();
exit(1);
}
reader = BufReader::new(file.unwrap()); // Reassignment. This is the line that fails.
}
// Rest of the code works with reader assuming a buffered input source.
}
事:
let mut reader : BufRead = io::stdin(); // Fails.
let mut reader : BufReader<Read> = io::stdin(); // Fails.
let mut reader : BufReader<_> = io::stdin(); // Fails
let mut reader : BufRead = io::stdin().lock(); // Fails later.
let mut reader = BufReader::new(io::stdin()); // Fails with type mismatch.
let mut reader = BufReader::new(io::stdin().lock()); // Fails with type mismatch.
我甚至試着將代碼解壓到自己的函數中,返回類型簽名失敗,出現類似的錯誤情況。如何在File
上創建一個「閱讀器」變量,該變量或者是BufferedReader
而不是stdio
或BufferedReader
而不是面向所有類型的錯誤?
答案如下:使用「箱子」類型。 Box是一個軟多態的引用(類似於C/C++風格語言中的指針)。 –