Out of內存錯誤android

Question

我正在android中工作。我正在設計一個程序將文件上傳到http服務器。

但是每當我運行這個程序並選擇一個大小稍大一點的文件時，這將產生以下錯誤。

java.lang.OutOfMemoryError 

    at java.io.ByteArrayOutputStream.expand(ByteArrayOutputStream.java:93) 


    at java.io.ByteArrayOutputStream.write(ByteArrayOutputStream.java:218) 

ERROR/AndroidRuntime(557):  at 

org.apache.harmony.luni.internal.net.www.protocol.http.HttpURLConnectionImpl$DefaultHttpOut 

putStream.write(HttpURLConnectionImpl.java:750) 


10-15 03:08:32.113: ERROR/AndroidRuntime(557):  at 

java.io.DataOutputStream.write(DataOutputStream.java:101) 

這是我的文件上傳： -

HttpURLConnection conn = null; 
     DataOutputStream dos = null; 

     DataInputStream inStream = null; 



     String existingFileName = "/mnt/sdcard/kuntal.PNG"; 


     Log.v("File upload",""+Environment.getExternalStorageDirectory().getAbsolutePath()); 
     String lineEnd = "\r\n"; 

     String twoHyphens = "--"; 

     String boundary = "*****"; 

     int bytesRead, bytesAvailable, bufferSize; 

     byte[] buffer; 

     int maxBufferSize = 1*1024*1024; 

     String responseFromServer = ""; 

     Log.v(TAG,"url= "); 

     String urlString = "http://192.168.1.126/MusicApplication/uploadmusic.php?title="+title_by_artist+"&category="+category_of_song+"&filename="+filename+"&price="+price_of_song+"&artist="+HomePageActivity.username; 
     Log.v(TAG,"url= "+urlString); 
     try 
     { 
     //------------------ CLIENT REQUEST 
     FileInputStream fileInputStream = new FileInputStream(new File(existingFileName)); 

     // open a URL connection to the Servlet 

     URL url = new URL(urlString); 

     // Open a HTTP connection to the URL 

     conn = (HttpURLConnection) url.openConnection(); 

     // Allow Inputs 
     conn.setDoInput(true); 

     // Allow Outputs 
     conn.setDoOutput(true); 

     conn.setUseCaches(false); 

     conn.setRequestMethod("POST"); 

     conn.setRequestProperty("Connection", "Keep-Alive"); 

     conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary); 

     dos = new DataOutputStream(conn.getOutputStream()); 
     dos.writeBytes(twoHyphens + boundary + lineEnd); 

     dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd); 

     dos.writeBytes(lineEnd); 

     // create a buffer of maximum size 

     bytesAvailable = fileInputStream.available(); 

     bufferSize = Math.min(bytesAvailable, maxBufferSize); 

     buffer = new byte[bufferSize]; 
     // read file and write it into form... 
     bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
     while (bytesRead > 0) 
     { 
      dos.write(buffer, 0, bufferSize); 

      bytesAvailable = fileInputStream.available(); 

      bufferSize = Math.min(bytesAvailable, maxBufferSize); 

      bytesRead = fileInputStream.read(buffer, 0, bufferSize); 

     } 
     // send multipart form data necesssary after file data... 
     dos.writeBytes(lineEnd); 
     dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd); 
     // close streams 
     Log.e("Debug","File is written"); 
     fileInputStream.close(); 
     dos.flush(); 
     dos.close(); 
     Toast.makeText(this, "File Successfully Uploaded", Toast.LENGTH_SHORT).show(); 

     } 
     catch (MalformedURLException ex) 
     { 
      Log.e("Debug", "error: " + ex.getMessage(), ex); 
     } 
     catch (IOException ioe) 
     { 
      Log.e("Debug", "error: " + ioe.getMessage(), ioe); 
     } 
     //------------------ read the SERVER RESPONSE 
     try { 
       inStream = new DataInputStream (conn.getInputStream()); 
       String str; 

       while ((str = inStream.readLine()) != null) 
       { 
        Log.e("Debug","Server Response "+str); 
       } 
       inStream.close(); 

     } 
     catch (IOException ioex){ 
      Log.e("Debug", "error: " + ioex.getMessage(), ioex); 
     } 
     } 




**and this is my php file for upload:-** 


if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) 
{ 



    echo "The file ". basename($_FILES['uploadedfile']['name']). 
    " has been uploaded"; 
    chmod ("Songs/".basename($_FILES['uploadedfile']['name']), 0644); 
} 
else 
{ 

    echo "filename: " . basename($_FILES['uploadedfile']['name']); 
    echo "target_path: " .$target_path; 
} 

請幫我我應該怎麼做才能上傳多一點大尺寸的文件等作爲MP3文件。 謝謝你提前...

Answer 1

我自己解決了我的問題。

這是由我在我的java文件所做的更改： -

 buffer = new byte[bufferSize]; 

    bufferSize = Math.min(bytesAvailable, maxBufferSize); 


    byte byt[]=new byte[bufferSize]; 

    fileInputStream.read(byt); 

    bytesRead = fileInputStream.read(buffer, 0, bufferSize); 

    dos.write(buffer, 0, bufferSize); 

在我的問題，這以下code被替換： -

while (bytesRead > 0) 
{ 


    dos.write(buffer, 0, bufferSize); 

    bytesAvailable = fileInputStream.available(); 

    bufferSize = Math.min(bytesAvailable, maxBufferSize); 

    bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
    } 

Answer 2

不幸的是這並沒有解決對我來說這個問題。然而，這個帖子：

Unable to write into DataOutputStream beyond a specific size - OutOfMemoryError

化險爲夷。您可以使用HttpURLConnection.setFixedLengthStreamingMode或HttpURLConnection.setChunkedStreamMode。否則，實際上沒有任何內容會傳輸到服務器，您將達到內存限制。

您可以使用WireShark實際檢查您的客戶端和服務器之間的流量，以確認這一點。

Answer 3

只需添加機器人：largeHeap =清單檔案中的 「真」

編號：largeHeap=true manifest tag not working?