SQL服務器 - 訂購情況

Question

我試圖讓下面的查詢，除了我想要的「柏林」，在列表的頂部出現

所以事實顯示由城市按字母順序排列的結果結果看起來像

• 柏林
• 阿爾及利亞
• 澳大利亞
• 斐濟
• 希臘
• ...

希望是有道理的，

我公司目前有以下...

SELECT CompanyName, City 
FROM customers 
ORDER BY case when City = 'Berlin' END 

Answer 1

SELECT CompanyName, City 
FROM customers 
ORDER BY case when City = 'Berlin' then 1 else 999 END asc 

Answer 2

差不多：

SELECT CompanyName, City 
FROM customers 
ORDER BY CASE WHEN City = 'Berlin' THEN 0 ELSE 1 END, City 

Answer 3

試試像

SELECT CompanyName, City 
FROM customers 
ORDER BY case when City = 'Berlin' THEN 0 ELSE 1 END, City 

Answer 4

SELECT CompanyName, City, CASE WHEN City = 'Berlin' THEN 0 ELSE 1 END AS Ordering 
FROM customers 
ORDER BY Ordering, City 

Answer 5

由於空字符串第一次出現在任何字符串排序列表，所有其他結果正常排序。所以這完美的作品：

SELECT CompanyName, City 
FROM customers 
ORDER BY CASE WHEN City = 'Berlin' THEN '' ELSE City END 

測試了：

CREATE TABLE customers (CompanyName VARCHAR(50), City VARCHAR(50)) 

INSERT INTO customers VALUES ('Customer1', 'Berlin') 
INSERT INTO customers VALUES ('Customer2', 'Algeria') 
INSERT INTO customers VALUES ('Customer3', 'Australia') 
INSERT INTO customers VALUES ('Customer4', 'Fiji') 
INSERT INTO customers VALUES ('Customer5', 'Greece') 

SELECT CompanyName, City 
FROM customers 
ORDER BY CASE WHEN City = 'Berlin' THEN '' ELSE City END 

-- OUPUT 
-- Customer1 Berlin 
-- Customer2 Algeria 
-- Customer3 Australia 
-- Customer4 Fiji 
-- Customer5 Greece 

Answer 6

有關使用聯盟如何？像這樣的東西，例如：

SELECT 1 as Weight, CompanyName, City FROM customers 
WHERE city='Berlin' 
UNION ALL 
SELECT 2 as Weight, CompanyName, City FROM 
customers 
WHERE city<>'Berlin' 
ORDER BY Weight, City