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我請求你原諒這麼冗長的查詢,但我迫切需要幫助。 當我運行下面的查詢時,我得到每日數據。但我希望每月的數據,使用LASTDAY, SUM,GROUP BY功能。 例如,如果我在#startDt#中選擇「20130501」,在#endDt#中選擇「20130701」,則應該給我3行累計結果;五月,六月和七月。誰能幫忙?如何使用SUM,GROUP BY函數獲取累積數據
SELECT X.*
FROM
(
SELECT
(CASE
WHEN DAY.DAY = 'SUM' THEN DAY.DAY
ELSE TO_CHAR (TO_DATE (DAY.DAY, 'YYYY-MM-DD'), 'YYYYMMDD')
END
) AS DAY,
DAY.WEEK,
MNOT.SUM_STD_CNT AS MNOT_CNT,
RSC.MOVIE_500K AS MOVIE_500K_CNT,
RSC.MOVIE_1M AS MOVIE_1M_CNT,
RSC.MOVIE AS MOVIE_CNT,
RSC.EXAM AS EXAM_CNT,
RSC.WEB AS WEB_CNT,
RSC.IMG AS IMG_CNT,
RSC.INTERRAC AS INTERRACTIVE_CNT,
RSC.DOC AS DOC_CNT,
MNOT.SUM_STD_CNT + RSC.MOVIE_500K + RSC.MOVIE_1M + RSC.MOVIE + RSC.EXAM + RSC.WEB + RSC.IMG + RSC.INTERRAC + RSC.DOC TOT_CNT
FROM
/* DATES */
(SELECT
TO_CHAR (TO_DATE (#startDt#,'YYYY-MM-DD')+LEVEL- 1, 'YYYYMMDD') AS DAY
FROM DUAL
CONNECT BY TO_DATE(#startDt#, 'YYYY-MM-DD') + LEVEL - 1 <![CDATA[<=]]> TO_DATE(#endDt#, 'YYYY-MM-DD')
UNION ALL
SELECT 'SUM', '' FROM DUAL
) DAY LEFT OUTER JOIN
/* RESOURCE */
(
SELECT
NVL(DT_G.COMM_DT, 'SUM') COMM_DT
,NVL(SUM(DT_G.MOVIE_500K), 0) AS MOVIE_500K
,NVL(SUM(DT_G.MOVIE_1M), 0) AS MOVIE_1M
,NVL(SUM(DT_G.MOVIE), 0) AS MOVIE
,NVL(SUM(DT_G.EXAM), 0) AS EXAM
,NVL(SUM(DT_G.DOC), 0) AS DOC
,NVL(SUM(DT_G.IMG), 0) AS IMG
,NVL(SUM(DT_G.WEB), 0) AS WEB
,NVL(SUM(DT_G.INTERRAC), 0) AS INTERRAC
FROM
(
SELECT
COMM_DT
, CASE SUMT.RSC_TP_DSCD WHEN 'RTP10' THEN SUMT.SUM_500K END MOVIE_500K
, CASE SUMT.RSC_TP_DSCD WHEN 'RTP10' THEN SUMT.SUM_1M END AS MOVIE_1M
, CASE SUMT.RSC_TP_DSCD WHEN 'RTP10' THEN SUMT.SUM_500K+SUMT.SUM_1M END AS MOVIE
, CASE SUMT.RSC_TP_DSCD WHEN 'RTP11' THEN SUMT.SUM_STD_CNT END AS EXAM
, CASE SUMT.RSC_TP_DSCD WHEN 'RTP12' THEN SUMT.SUM_STD_CNT END AS DOC
, CASE SUMT.RSC_TP_DSCD WHEN 'RTP13' THEN SUMT.SUM_STD_CNT END AS IMG
, CASE SUMT.RSC_TP_DSCD WHEN 'RTP14' THEN SUMT.SUM_STD_CNT END AS WEB
, CASE SUMT.RSC_TP_DSCD WHEN 'RTP01' THEN SUMT.SUM_STD_CNT END AS INTERRAC
FROM (
SELECT RSC_TP_DSCD, SUM(STDY_CNT) AS SUM_STD_CNT, SUM(MOVIE_STDY_CNT_N1M) AS SUM_1M, SUM(MOVIE_STDY_CNT_N500K) AS SUM_500K, COMM_DT
FROM (
SELECT RSC_SNO, STDY_CNT, MOVIE_STDY_CNT_N1M, MOVIE_STDY_CNT_N500K, COMM_DT
FROM LRMS.V_EBSM_PKG_RSC_COMM_CNT
WHERE PKG_SNO = 0 AND RSC_SNO != 0
AND COMM_DT BETWEEN TO_CHAR(TO_DATE(#startDt#, 'YYYY-MM-DD'), 'YYYYMMDD') AND TO_CHAR(TO_DATE(#endDt#, 'YYYY-MM-DD'), 'YYYYMMDD')
) CNT
LEFT OUTER JOIN LRMS.V_LRRM_RSC RSC ON CNT.RSC_SNO = RSC.RSC_SNO
GROUP BY RSC_TP_DSCD, COMM_DT
) SUMT
) DT_G
GROUP BY ROLLUP(DT_G.COMM_DT)
) RSC ON DAY.DAY = RSC.COMM_DT
LEFT OUTER JOIN
(
SELECT NVL(SUM(STDY_CNT), 0) AS SUM_STD_CNT, NVL(COMM_DT, 'SUM') COMM_DT
FROM LRMS.V_EBSM_PKG_RSC_COMM_CNT
WHERE PKG_SNO != 0 AND RSC_SNO = 0
AND COMM_DT BETWEEN TO_CHAR(TO_DATE(#startDt#, 'YYYY-MM-DD'), 'YYYYMMDD') AND TO_CHAR(TO_DATE(#endDt#, 'YYYY-MM-DD'), 'YYYYMMDD')
GROUP BY ROLLUP(COMM_DT)
) MNOT ON DAY.DAY = MNOT.COMM_DT
) X
WHERE 1=1
and X.TOT_CNT IS NOT NULL
告訴我它是什麼?我可以幫助你更多。 –
感謝您的幫助,謝謝。但我想知道幾件事情。 1)整個查詢進入「YOURQUERY」? 2)DATENAME(MONTH,DAY)是什麼,因爲我的參數是#startDt#和#endDt# – user2470075
1.如果你想對你的白天明智查詢的結果應用group by,那麼你應該把整個查詢。 2.您生成了一個列名稱「日」。我申請月份名稱功能,並在其上應用分組。所以結果將月份明智地和其他列應用總和。 –