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我正在一個頁面上構建多個倒計時時鐘。倒計時鐘的數量每天都有所不同，所以我需要在php的「while」代碼中多次調用javascript以產生不同的時鐘。下面的代碼工作，但它是基於知道有多少時鐘我之前需要啓動：如何增加一個php內循環的javascript變量標題
<script language="javascript" src="countdown.js"></script>
<script language="javascript">
var cd1 = new countdown('cd1');
cd1.Div = "clock1";
cd1.TargetDate = "<?php echo "$clocktime"; ?>";
cd1.DisplayFormat = "%%D%% days, %%H%% hours, %%M%% minutes, %%S%% seconds until event AAA happens";
</script>
<div id="clockwrapper"><div id="clock1">[clock]</div></div>
<script language="javascript" src="countdown.js"></script>
<script language="javascript">
var cd2 = new countdown('cd2');
cd2.Div = "clock2";
cd2.TargetDate = "02/01/2011 5:30:30 PM";
cd2.DisplayFormat = "%%D%% days, %%H%% hours, %%M%% minutes, %%S%% seconds until event BBB happens...";
</script>
<div id="clockwrapper"><div id="clock2">[clock]</div></div>
所以，如果我繼續打電話以上（在它CD1的代碼）的JavaScript所有以前的「CD1」時鐘改變最新的時鐘，因爲它被覆蓋。不知何故，我需要在我的「while」循環中調用JavaScript，並將cd1變成cd2，然後cd3，以便時鐘按照它們應有的方式工作。 我該如何去做這件事？我不知道如何多次調用javascript，並在javascript中增加變量cd1。我嘗試了這樣的東西，但無法讓它工作。
$id=mysql_result($result,$i,"id");
while($id){
$cd = ("$cd"."$id");
?>
<script language="javascript" src="countdown.js"></script>
<script language="javascript">
var <?php echo "$cd"; ?> = new countdown('<?php echo "$cd"; ?>');
....
</script>
<div id="clockwrapper"><div id="<?php echo "$cd"; ?>">[clock]</div></div>
<?php
$id=mysql_result($result,$i,"id");
}
?>
當然有一些簡單的方法來解決這個問題，我不知道。
-------------------------------編輯-------------- ---------------------
添加countdown.js下面這可能有助於
/*
Author: Robert Hashemian (http://www.hashemian.com/)
Modified by: Munsifali Rashid (http://www.munit.co.uk/)
*/
function countdown(obj)
{
this.obj = obj;
this.Div = "clock";
this.BackColor = "white";
this.ForeColor = "black";
this.TargetDate = "12/31/2020 5:00 AM";
this.DisplayFormat = "%%D%% Days, %%H%% Hours, %%M%% Minutes, %%S%% Seconds.";
this.CountActive = true;
this.DisplayStr;
this.Calcage = cd_Calcage;
this.CountBack = cd_CountBack;
this.Setup = cd_Setup;
}
function cd_Calcage(secs, num1, num2)
{
s = ((Math.floor(secs/num1))%num2).toString();
if (s.length < 2) s = "0" + s;
return (s);
}
function cd_CountBack(secs)
{
this.DisplayStr = this.DisplayFormat.replace(/%%D%%/g, this.Calcage(secs,86400,100000));
this.DisplayStr = this.DisplayStr.replace(/%%H%%/g, this.Calcage(secs,3600,24));
this.DisplayStr = this.DisplayStr.replace(/%%M%%/g, this.Calcage(secs,60,60));
this.DisplayStr = this.DisplayStr.replace(/%%S%%/g, this.Calcage(secs,1,60));
document.getElementById(this.Div).innerHTML = this.DisplayStr;
if (this.CountActive) setTimeout(this.obj +".CountBack(" + (secs-1) + ")", 990);
}
function cd_Setup()
{
var dthen = new Date(this.TargetDate);
var dnow = new Date();
ddiff = new Date(dthen-dnow);
gsecs = Math.floor(ddiff.valueOf()/1000);
this.CountBack(gsecs);
}
感謝
請永遠不要把$瓦爾在「引號」中是醜陋的，會讓你的腳本變慢。 echo $ var;工作同樣好！你發佈的snipper的輸出是什麼？它是否做任何事情？ – gnur 2011-02-02 06:57:16