RaptureXML怪異的行爲

Question

我得到一個錯誤（當然它不顯示，剛剛崩潰了應用程序，在控制檯上沒有資料）發生 似乎每當我從RXML的rootXML調用該方法迭代：

-(void)valueSearch { 
    //FIRST CONNECTION 
    NSString *serverAddress = @"http://www.commix.com.br/clientes/grupoglobo/apple/valor.xml"; 
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:serverAddress] 
                 cachePolicy:NSURLRequestReloadIgnoringLocalAndRemoteCacheData 
                timeoutInterval:10]; 
NSError *requestError; 
    NSURLResponse *urlResponse = nil; 

    response = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&requestError]; 

    //SECOND CONNECTION - Just an encapsulated form of the first, since i use it in other parts 
    // of the code 
    response = [self requestWithParameters:@"valor.xml"]; 

    //i just uncommented both. but actually only one (connection) runs. 

    //Creation of the rooXML so i can grab the info i need 
    RXMLElement *rootXML = [RXMLElement elementFromXMLData:response]; 
    //This array is where i'll keep the info from the files. 
    //it`s deallocated at the end in dealloc 
    searchResult = [[NSMutableArray alloc] init]; 

    //This is the culprit. Atleast it seems so, since putting NSLog before and after 
    //revealed so. 
    [rootXML iterate:@"valor" usingBlock: ^(RXMLElement *valor) { 
     NSLog(@"valor: %@", [valor child:@"nome"].text); 
     [searchResult addObject:[valor child:@"nome"].text]; 
    }]; 
} 

事情是，當我評論requestWithParameters並使用正常的非封裝樣式（//第一連接）我不會收到錯誤。但如果我使用第二個，當程序達到[rootXML iterate: [...]]時，它會在沒有任何警告的情況下崩潰。

使用RaptureXML：https://github.com/ZaBlanc/RaptureXML

它還發生在碼的另一部分：

-(void)vehicleSearch { 

    NSString *path = [[NSBundle mainBundle] pathForResource:@"idArray" ofType:@"plist"]; 
    NSMutableArray *idArray = [[NSMutableArray alloc] initWithContentsOfFile:path]; 

    NSMutableString *serverAddress = (@"http://www.commix.com.br/clientes/grupoglobo/apple/modelo.php?marc=%@",[idArray objectAtIndex:0]); 
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:serverAddress] 
                 cachePolicy:NSURLRequestReloadIgnoringLocalAndRemoteCacheData 
                timeoutInterval:10]; 

NSError *requestError; 
    NSURLResponse *urlResponse = nil; 
    response = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:&requestError]; 

    RXMLElement *rootXML = [RXMLElement elementFromXMLData:response]; 
    searchResult = [[NSMutableArray alloc] init]; 

    [rootXML iterate:@"modelo" usingBlock: ^(RXMLElement *modelo) { 
     NSLog(@"modelo: %@", [modelo child:@"nome"].text); 
     [searchResult addObject:[modelo child:@"nome"].text]; 
    }]; 

    [idArray release]; 
} 

發生在同一行[rootXML iterate:]。

對不起，泄漏和東西，我沒經驗（這就是爲什麼我在這裏），謝謝！

編輯： 其實罪魁禍首是線

NSMutableString *serverAddress = (@"http://www.commix.com.br/clientes/grupoglobo/apple/modelo.php?marc=%@",[idArray objectAtIndex:0]); 

，如果我直接傳遞參數，不變量，它的工作原理：

NSMutableString *serverAddress = (@"http://www.commix.com.br/clientes/grupoglobo/apple/modelo.php?marc=4"); 

它正確顯示。

Answer 1

您確定,[idArray objectAtIndex:0]是NSString嗎？ 嘗試使用

[NSString stringWithFormat:@"http://www.commix.com.br/clientes/grupoglobo/apple/modelo.php?marc=%@",[idArray objectAtIndex:0]];` 

甚至

[NSString stringWithFormat:@"http://www.commix.com.br/clientes/grupoglobo/apple/modelo.php?marc=%@",[[idArray objectAtIndex:0]stringValue]]; 

Answer 2

response = [self requestWithParameters:@"valor.xml"]; 

如果response是一個屬性使用self.response否則就會有內存泄漏問題。