java7鑽石運算符轉換編譯錯誤

Question

我想將當前的代碼轉換爲Java7 diamond operator。 我有以下正則表達式來查找和替換。

尋找

new (\w+)<.+> 

替換：

new $1<> 

問題是，它是 越來越取代了匿名類爲好。因爲這個我得到編譯錯誤。 那麼如何編寫避免內部類的正則表達式呢？

Answer 1

試試這個：(?s)new (\w+)<.+>(\(.*?\);)

String test = "List<String> t = new ArrayList<String>();"; 
System.out.println(test.replaceAll("(?s)new (\\w+)<.+>(\\(.*?\\);)", "new $1<>$2")); 

String test2 = "List<String> t = new ArrayList<String>(getList());"; 
System.out.println(test2.replaceAll("(?s)new (\\w+)<.+>(\\(.*?\\);)", "new $1<>$2")); 

String test3 = "List<String> t = new ArrayList<String>(\n\tgetList(\n\t\tanotherMethod()\n\t)\n);"; 
System.out.println(test3.replaceAll("(?s)new (\\w+)<.+>(\\(.*?\\);)", "new $1<>$2")); 

String test4 = "List<String> t = new List<String>(){ /* implementation */ };"; 
System.out.println(test4.replaceAll("(?s)new (\\w+)<.+>(\\(.*?\\);)", "new $1<>$2")); 

String test5 = "List<String> t = new List<String>()\n{\n\t/* implementation */\n};"; 
System.out.println(test5.replaceAll("(?s)new (\\w+)<.+>(\\(.*?\\);)", "new $1<>$2")); 

它打印：

List<String> t = new ArrayList<>(); 
List<String> t = new ArrayList<>(getList()); 
List<String> t = new ArrayList<>(
    getList(
     anotherMethod() 
    ) 
); 
List<String> t = new List<String>(){ /* implementation */ }; 
List<String> t = new List<String>() 
{ 
    /* implementation */ 
};