好的,在這裏。我試圖讓一個觀點,即表明這一點:MySQL - 在視圖中獲取不同的行
+---------+---------+-------+--------+------------+---------------------+---------------+-------------------+-------------+
| post_id | status | title | body | ip_address | time_stamp | category_name | sub_category_name | post_type |
+---------+---------+-------+--------+------------+---------------------+---------------+-------------------+-------------+
| 1 | enabled | test | test 2 | | 2010-05-20 01:22:17 | For Sale | Computers | transaction |
+---------+---------+-------+--------+------------+---------------------+---------------+-------------------+-------------+
1 row in set (0.00 sec)
是這樣做的查詢是:
SELECT post.id AS post_id,
post.status AS status,
post_data.title AS title,
post_data.body AS body,
post_data.ip_address AS ip_address,
post_data.time_stamp AS time_stamp,
post_category.name AS category_name,
post_sub_category.name AS sub_category_name,
post_category.type AS post_type
FROM post,
(
SELECT * FROM post_data WHERE post_data.post_id = post_id ORDER BY post_data.post_id DESC LIMIT 1
) AS post_data,
post_sub_category,
post_category
WHERE
post.sub_category_id = post_sub_category.id AND
post_sub_category.category_id = post_category.id
但是,因爲它有一個嵌套查詢,我不能用它作爲視圖。目前我能想到的最好的查詢工作的看法是這樣的:
SELECT
post.id AS post_id,
post.status AS status,
post_data.title AS title,
post_data.body AS body,
post_data.ip_address AS ip_address,
post_data.time_stamp AS time_stamp,
post_category.name AS category_name,
post_sub_category.name AS sub_category_name,
post_category.type AS post_type
FROM post,
post_data,
post_sub_category,
post_category
WHERE
post.sub_category_id = post_sub_category.id AND
post_sub_category.category_id = post_category.id
ORDER BY post_data.id DESC
但是,這只是返回:
+---------+---------+-------+-----------+----------------+---------------------+---------------+-------------------+-------------+
| post_id | status | title | body | ip_address | time_stamp | category_name | sub_category_name | post_type |
+---------+---------+-------+-----------+----------------+---------------------+---------------+-------------------+-------------+
| 1 | enabled | test | test 2 | | 2010-05-20 01:22:17 | For Sale | Computers | transaction |
| 1 | enabled | TEST | TEST BODY | 192.168.10.155 | 2010-05-19 23:09:15 | For Sale | Computers | transaction |
+---------+---------+-------+-----------+----------------+---------------------+---------------+-------------------+-------------+
2 rows in set (0.00 sec)
我只希望每POST_ID一排,我希望它是最新的一個。有沒有人有什麼建議?在處理軟刪除等問題時,我正在使用視圖來嘗試並使生活更輕鬆,並且從理論上講,還需要從長遠角度查詢我想要的數據。
非常感謝!