如何獲得文字和某些標籤

Question

鑑於像

"<p> >this line starts with an arrow <br /> this line does not </p>" 

或

"<p> >this line starts with an arrow </p> <p> this line does not </p>" 

字符串我怎樣才能找到帶箭頭開始和一個div

包圍他們的字裏行間替換文本

，使之成爲：

"<p> <div> >this line starts with an arrow </div> <br /> this line does not </p> 

Answer 1

因爲它是一個HTML你解析，使用工具 - HTML解析r，如BeautifulSoup。

使用find_all()地發現，與>開始，wrap()它們與新的div標籤的所有文本節點：

from bs4 import BeautifulSoup 

data = "<p> >this line starts with an arrow <br /> this line does not </p>" 

soup = BeautifulSoup(data) 
for item in soup.find_all(text=lambda x: x.strip().startswith('>')): 
    item.wrap(soup.new_tag('div')) 

print soup.prettify() 

打印：

<p> 
    <div> 
    >this line starts with an arrow 
    </div> 
    <br/> 
    this line does not 
</p> 

Answer 2

你可以用>\s+(>.*?)<嘗試正則表達式模式。

import re 
regex = re.compile("\\>\\s{1,}(\\>.{0,}?)\\<") 
testString = "" # fill this in 
matchArray = regex.findall(testString) 
# the matchArray variable contains the list of matches 

並用<div> matched_group </div>替換匹配的組。這裏模式尋找> >和<內的任何內容。

這裏是debuggex

Answer 3

你可以試試這個表達式演示，

>(\w[^<]*) 

DEMO

Python代碼會是這樣，

>>> import re 
>>> str = '"<p> >this line starts with an arrow <br /> this line does not </p>"' 
>>> m = re.sub(r'>(\w[^<]*)', r"<div> >\1</div> ", str) 
>>> m 
'"<p> <div> >this line starts with an arrow </div> <br /> this line does not </p>"'