如何獲得SQL Server中某些字符之間的子串

Question

我有一個字符串com.test.edu.personal.SomeException: this is some error: test message。我需要得到字符串爲SomeException: this is some error。

我有我的代碼的煩惱：

declare @col varchar(100) 

set @col = 'com.test.edu.personal.SomeException: this is some error: test message' 

SELECT 
    SUBSTRING(@col, 
       LEN(@col) - CHARINDEX(':', @col) - CHARINDEX(':', REVERSE(@col)), 
       LEN(@col) - LEN(LEFT(@col, CHARINDEX ('.', @col))) - LEN(RIGHT(@col, LEN(@col) - CHARINDEX (':', @col)))); 

我越來越nal.SomeException: this is some - 我在這裏的東西

Answer 1

declare @col varchar(100) 
set @col = 'com.test.edu.personal.SomeException: this is some error: test message' 

Select Substring(@col,Len((substring(@col,1,charindex(':',@col)))) - CharIndex(Reverse('.'), Reverse((substring(@col,1,charindex(':',@col)))))-len('.')+3 ,len(@col)) 

返回

SomeException: this is some error: test message