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我試圖打印出一些數據 所以我的代碼是XML在Java解析使用XPath
private static final DocumentBuilderFactory DOCUMENT_BUILDER_FACTORY = DocumentBuilderFactory.newInstance();
private static final XPathFactory XPATH_FACTORY = XPathFactory.newInstance();
public void parseXml(String urlPath) throws Exception {
URL url = new URL(urlPath);
URLConnection connection = url.openConnection();
DocumentBuilder db = DOCUMENT_BUILDER_FACTORY.newDocumentBuilder();
final Document document = db.parse(connection.getInputStream());
XPath xPathEvaluator = XPATH_FACTORY.newXPath();
XPathExpression nameExpr = xPathEvaluator.compile("lfm/results/trackmatches/track");
NodeList tracksinfoNodes = (NodeList) nameExpr.evaluate(document, XPathConstants.NODESET);
for (int i = 0; i < tracksinfoNodes.getLength(); i++) {
Node trackNameNode = tracksinfoNodes.item(i);
System.out.println(String.format("Track Name: %s" , trackNameNode.getTextContent()));
}
}
所以它將打印我喜歡本作的第一循環
Track Name:
I Believe in You
Neil Young
http://www.last.fm/music/Neil+Young/_/I+Believe+in+You
0
90540
http://userserve-ak.last.fm/serve/34s/65285990.png
http://userserve-ak.last.fm/serve/64s/65285990.png
http://userserve-ak.last.fm/serve/126/65285990.png
http://userserve-ak.last.fm/serve/300x300/65285990.png
的URL我我正在使用的是http://ws.audioscrobbler.com/2.0/?method=track.search&track=Believe&api_key=b25b959554ed76058ac220b7b2e0a026
所以我想要做的就是讓eveyone獨自一人,像這樣
song : I Believe in You
artist :Neil Young
link : http://www.last.fm/music/Neil+Young/_/I+Believe+in+You
something: 0
views: 90540
linkimg : http://userserve-ak.last.fm/serve/34s/65285990.png
..
..
是那裏有反正我可以舉例來說,它的節點名稱得到的值,如果我想用歌曲名來替換標題例如 感謝 – Peril
出現答案在códgio我提供的是等於你所需要的。我不明白評論中解釋的困難。 –