我試圖解析Java編寫,但代碼SOAP請求的Java命名空間沒有返回任何節點 這裏是代碼有誰能夠找到錯誤解析XML使用XPath的
String xml="<soapenv:Envelope xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:ser=\"http://services.web.post.list.com\"><soapenv:Header><authInfo xsi:type=\"soap:authentication\" xmlns:soap=\"http://list.com/services/SoapRequestProcessor\"><!--You may enter the following 2 items in any order--><username xsi:type=\"xsd:string\">[email protected]</username><password xsi:type=\"xsd:string\">PfasdfRem91</password></authInfo></soapenv:Header></soapenv:Envelope>";
System.out.println(xml);
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
domFactory.setNamespaceAware(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document doc = builder.parse(new InputSource(new StringReader(xml)));
XPath xpath = XPathFactory.newInstance().newXPath();
// XPath Query for showing all nodes value
try
{
XPathExpression expr = xpath.compile("/soapenv:Envelope/soapenv:Header/authInfo/password");
Object result = expr.evaluate(doc, XPathConstants.NODESET);
NodeList nodes = (NodeList) result;
System.out.println("Got " + nodes.getLength() + " nodes");
// System.out.println(nodes.item(0).getNodeValue());
}
catch(Exception E)
{
System.out.println(E);
}
嘗試這些: http://stackoverflow.com/questions/5673708/parsing-xml-with-xpath-in-java-get-data-from-xml-file-with-xpath-and-nodelist http://stackoverflow.com /疑問句tions/5519766/search-in-xml-file-with-xpath-in-android/5664438#5664438 – alibenmessaoud 2012-07-25 07:50:47
謝謝我會試試這些 – Raheel 2012-07-25 07:54:51