如何在計數查詢結果中包含0

我有4個表存儲4種請求：延時（TO），會議（MT），訂單和旅行（TR）。如何在計數查詢結果中包含0

我要計算每個表中每種類型的請求總數在過去30天：

SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM [Timeoff] 
    WHERE [requestType] = 'TO' AND CAST([timeoffCreatedTime] AS DATE) >= CAST(DateAdd(DAY,-30,Getdate()) AS DATE) GROUP BY [requestType] 
    UNION ALL 
    SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM [Meeting] 
    WHERE [requestType] = 'MT' AND CAST([meetingCreatedTime] AS DATE) >= CAST(DateAdd(DAY,-30,Getdate()) AS DATE) GROUP BY [requestType] 
    UNION ALL 
    SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM [PO] 
    WHERE [requestType] = 'PO' AND CAST([poCreatedTime] AS DATE) >= CAST(DateAdd(DAY,-30,Getdate()) AS DATE) GROUP BY [requestType] 
    UNION ALL 
    SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM [Travel] 
    WHERE [requestType] = 'TR' AND CAST([travelCreatedTime] AS DATE) >= CAST(DateAdd(DAY,-30,Getdate()) AS DATE) GROUP BY [requestType]

問題是，如果計數爲0，那麼它不會在結果顯示在所有，例如，如果會議請求的數量= 0，那麼我唯一有此作爲的結果：

怎樣包括在結果中的0值，所以我有類似的東西（如會議MT數= 0）：

的RequestType ---計數

TO ------------- 30

MT ------------- 0

PO ------------- 19

TR ------------- 9

來源

2016-01-28 Ronaldinho Learn Coding

你爲什麼要寫Group By子句？我認爲這不需要，因爲我的書面解決方案 –

你必須從你的查詢中刪除GROUP BY，它不需要！你的查詢應該只是：

SELECT 'TO' AS [requestType], COUNT ([requestType]) As 'Count' 
    FROM [Timeoff] 
    WHERE [requestType] = 'TO' AND CAST([timeoffCreaime] ATE) >= CASt(DAY,-30,Gte()) ATE) 
    UNION ALL 
    SELECT 'Meeting' AS [requestType], COUNT ([requestType]) As 'Count' 
    FROM [Meeting] 
    WHERE [requestType] = 'Meeting' AND CAST([meetingCreaime] ATE) >= CASt(DAY,-30,Gte()) ATE) 
    UNION ALL 
    SELECT 'PO' AS [requestType], COUNT ([requestType]) As 'Count' 
    FROM [PO] 
    WHERE [requestType] = 'PO' AND CAST([poCreaime] ATE) >= CASt(DAY,-30,Gte()) ATE) 
    UNION ALL 
    SELECT 'TR' AS [requestType], COUNT ([requestType]) As 'Count' 
    FROM [Travel] 
    WHERE [requestType] = 'TR' AND CAST([travelCreaime] ATE) >= CASt(DAY,-30,Gte()) ATE)

來源

2016-01-29 00:00:59

它已經這樣硬編碼，他需要它在WHERE過濾器中，因爲我不知道他的業務邏輯。 –

我回滾了編輯，使其恢復到原始狀態。爲了使你的代碼正常工作，你需要從select語句中刪除'RequestType'，並對'RequestType'進行硬編碼。 –

@AnupAgrawal爲什麼你編輯我的解決方案，其中包含requestType的編碼...然後要求這麼做？ :) 羅納爾迪尼奧代碼工作正常，只需要刪除GROUP BY子句以獲得結果中的0計數。我認爲這應該是一個正確的答案。謝謝 –

您可以做一個外連接上每個查詢類似於（選擇1）

SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM (select 1 as foo) bar 
    LEFT JOIN [CTEite].[dbo].[Timeoff] ON 1=1 
    WHERE [requestType] = 'TO' AND CAST([timeoffCreaime] ATE) >= CASt(DAY,-

或UNION和總和

WITH foo AS(
SELECT 'TO' as [requestType], 0 as [Count] 
UNION ALL 
SELECT 'MT', 0 
UNION ALL 
.... 
) 
SELECT [requestType], sum([Count]) 
FROM 
(SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM [CTEite].[dbo].[Timeoff] 
    WHERE [requestType] = 'TO' AND CAST([timeoffCreaime] ATE) >= CASt(DAY,-30,Gte()) ATE) GROUP BY [requestType] 
    UNION ALL 
    SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM [CTEite].[dbo].[Meeting] 
    WHERE [requestType] = 'Meeting' AND CAST([meetingCreaime] ATE) >= CASt(DAY,-30,Gte()) ATE) GROUP BY [requestType] 
    UNION ALL 
    SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM [CTEite].[dbo].[PO] 
    WHERE [requestType] = 'PO' AND CAST([poCreaime] ATE) >= CASt(DAY,-30,Gte()) ATE) GROUP BY [requestType] 
    UNION ALL 
    SELECT [requestType], COUNT ([requestType]) As 'Count' 
    FROM [CTEite].[dbo].[Travel] 
    WHERE [requestType] = 'TR' AND CAST([travelCreaime] ATE) >= CASt(DAY,-30,Gte()) ATE) GROUP BY [requestType] 
UNION SELECT * FROM foo) 
GROUP BY [requestType]

來源

2016-01-28 23:23:36

如何在計數查詢結果中包含0

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