SQL LIKE無法正常返回

Question

$vendor=$this->db->query("SELECT code from `sources` where uniquevendor=1"); 
foreach($vendor->result() as $vendor_data) { 

    $data['queryItem']=$this->db->query("SELECT sourcing, `item_sku`, sum(quantity)as total FROM `item` WHERE `item_sku` like '$vendor_data->code%' AND quantity<0 group by `item_sku` order by total asc;"); 
} 

$venodor有18個供應商。但在$data['queryItem'] Like運算符的工作只能針對最後一個上一個供應商的名稱和返回值。爲什麼會這樣呢？

Answer 1

保持到當前的結構我想你需要的是這樣的：

$vendor=$this->db->query("SELECT code from `sources` where uniquevendor=1"); 
foreach($vendor->result() as $vendor_data) { 
    $data[$vendor_data->code]=$this->db->query("SELECT sourcing, `item_sku`, sum(quantity)as total FROM `item` WHERE `item_sku` like '$vendor_data->code%' AND quantity<0 group by `item_sku` order by total asc;"); 
} 

Answer 2

請給一個嘗試

select b.sourcing, b.item_sku, sum(b.quantity)as total from sources a left join item on a.code = b.item_sku 

我不知道你爲什麼不使用連接。