與註釋

Question

Hibernate的多態性集合映射我有我的客戶一個抽象類：

@Entity 
public class AbstractClientEntity extends AbstractPersonneEntity implements Demarchable { 

@Column(name="ID_REFERENT") 
private AbstractEmployeEntity referent; 
... 

具體類看起來是這樣的：

@Entity 
@DiscriminatorValue(TypePersonne.Values.INVITE) 
public class InviteEntity extends AbstractClientEntity implements Invitable { 
... 

和

@Entity 
@DiscriminatorValue(TypePersonne.Values.AUTRE) 
public class AutreClientEntity extends AbstractClientEntity { 

，我有我的員工擁有一組AbstractClientEntity的其他抽象類：

@Entity 
public class AbstractEmployeEntity extends AbstractPersonneEntity { 

@ManyToOne(fetch = FetchType.LAZY) 
@JoinColumn(name = "ID_REFERENT", nullable = false) 
private MonitriceEntity monitrice = new MonitriceEntity(); 

@OneToMany(fetch = FetchType.LAZY, mappedBy = "referent") 
private Set<AbstractClientEntity> listeClients = new HashSet<AbstractClientEntity>(); 
... 

問題是，當我特里結構運行我的web應用程序，這將引發異常：

org.springframework.beans.factory.BeanCreationException: Could not autowire field: private org.hibernate.SessionFactory ch.tupperware.tuppergestion.dao.AbstractDao.sessionFactory; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'sessionFactory' defined in ServletContext resource [/WEB-INF/config/tupper-servlet.xml]: Invocation of init method failed; nested exception is org.hibernate.MappingException: Could not determine type for: ch.tupperware.tuppergestion.entity.AbstractEmployeEntity, at table: PERSONNE, for columns: [org.hibernate.mapping.Column(ID_REFERENT)] 
    org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor$AutowiredFieldElement.inject(AutowiredAnnotationBeanPostProcessor.java:507) 
    org.springframework.beans.factory.annotation.InjectionMetadata.inject(InjectionMetadata.java:84) 
    org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor.postProcessPropertyValues(AutowiredAnnotationBeanPostProcessor.java:283) 
    org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1055) 
    org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:511) 
    org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:450) 
    org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:290) 
    org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) 
    org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:287) 
    org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:189) 
    org.springframework.beans.factory.support.DefaultListableBeanFactory.findAutowireCandidates(DefaultListableBeanFactory.java:825) 
    org.springframework.beans.factory.support.DefaultListableBeanFactory.doResolveDependency(DefaultListableBeanFactory.java:767) 
    org.springframework.beans.factory.support.DefaultListableBeanFactory.resolveDependency(DefaultListableBeanFactory.java:685) 

我不知道我怎樣才能解決這個問題？

謝謝爲幫助

Answer 1

最後，我會回答我的問題，並希望這將幫助別人......

多次嘗試後，我採用的解決方案有一個列表中爲每個具體類我在我的AbstractEmployeEntity管理：

@Entity 
public class AbstractEmployeEntity extends AbstractPersonneEntity { 

@OneToMany(fetch = FetchType.LAZY, mappedBy = "referent") 
private Set<HotesseEntity> listeHotesse = new HashSet<HotesseEntity>(); 

@OneToMany(fetch = FetchType.LAZY, mappedBy = "referent") 
private Set<InviteEntity> listeInvites = new HashSet<InviteEntity>(); 

@OneToMany(fetch = FetchType.LAZY, mappedBy = "referent") 
private Set<AutreClientEntity> listeAutreClients = new HashSet<AutreClientEntity>(); 

希望這會幫助別人......

Answer 2

的原因是顯而易見的：

Invocation of init method failed; nested exception is org.hibernate.MappingException: Could not determine type for: ch.tupperware.tuppergestion.entity.AbstractEmployeEntity, at table: PERSONNE, for columns: [org.hibernate.mapping.Column(ID_REFERENT)] 

您的班級ch.tupperware.tuppergestion.entity.AbstractEmployeEntity未在您的表PERSONNE中找到列ID_REFERENT。

你是怎麼映射你的AbstractEmployeEntity類的。如果它是一個抽象類，爲什麼不把它映射到@MappedSuperclass？