SQL Server 2008 R2：查找表中第二大數

Question

我用下面的表格查找一些數據，找到第二大數字。

表：

ColA 
--------- 
3 
23 
43 
673 
173 
373 
273 

Answer 1

使用此：

select * from 
(select colA , row_number() over(order by colA desc) as rn from Table) T 
where T.rn=2 

感謝馬丁/ dnoeth的評論：

它可與最多2個inetegers

問題

使用此：

select * from 
    (select colA , DENSE_RANK() OVER (ORDER BY colA ) as rn from Table) T 
    where T.rn=2 

附加信息：（一勞永逸（學習吧！，我總是用它））：

DECLARE @t TABLE(NAME NVARCHAR(MAX),val money) 

insert INTO @t SELECT 'a',100 
insert INTO @t SELECT 'a',100 
insert INTO @t SELECT 'a',100 
insert INTO @t SELECT 'a',100 
insert INTO @t SELECT 'b',200 
insert INTO @t SELECT 'b',200 
insert INTO @t SELECT 'd',400 
insert INTO @t SELECT 'e',500 
insert INTO @t SELECT 'f',600 
select Name, 
     val, 
     ROW_NUMBER() OVER (PARTITION BY NAME ORDER BY name), 
     val/ SUM(val) OVER(PARTITION BY NAME) AS '1AgainstTotalHimself', 
     val/ SUM(val) OVER() AS '1AgainstOthers' , 
     NTILE(2) OVER (PARTITION BY NAME ORDER BY name) AS 'ntile2' , 
     NTILE(2) OVER (ORDER BY name) AS 'ntile' , -- (9%2=1 , so group #1 will get more number) 
     RANK() OVER (ORDER BY name ) AS Rank, 
     DENSE_RANK() OVER (ORDER BY name) AS DENSERANK 

from @t 

結果：解決

Answer 2

的一種方式，這將是

with cte as (
    select ColA, 
      Row_number() over(order by ColA DESC) As rn 
    FROM Table 
) 

SELECT ColA 
FROM cte 
WHERE rn = 2 

更新 馬丁的正確意見後，這裏是一個更好的答案：

Select top 1 ColA 
From YourTable 
WHERE ColA < (
    SELECT MAX(ColA) 
    FROM YourTable 
) 
ORDER BY ColA DESC