優雅的方式去掉括號中的值在Python中

Question

Line = "A[0x04] Va [0xf] 

如何將這些線條拆分爲兩個變量，分別爲0x04和0xf？

嘗試的解決方案：

for line in sys.stdin: 
    line.strip("[]").split 

Answer 1

使用列表理解：

>>> Line = "A[0x04] Va [0xf]" 
>>> [x.partition(']')[0] for x in Line.split('[') if ']' in x] 
['0x04', '0xf'] 

Answer 2

我會用re.findall：

>>> from re import findall 
>>> Line = "A[0x04] Va [0xf] " 
>>> findall("\[([^\]]*)\]", Line) 
['0x04', '0xf'] 
>>> x,y = findall("\[([^\]]*)\]", Line) 
>>> x 
'0x04' 
>>> y 
'0xf' 
>>> 

下面是正則表達式模式的崩潰：

\[  # [ 
([^\]]*) # Capture group to get zero or more characters that are not ] 
\]  # ] 

Answer 3

import re 
re.findall("\[[^\]]*\]", Line) 

Answer 4

In [36]: %paste 
answer = [] 
take = False 
line = "A[0x04] Va [0xf] " 
start = 0 
for i,char in enumerate(line): 
    if not take: 
     if char == '[' : 
      take = True 
      start = i+1 
    else: 
     if char == ']': 
      take = False 
      answer.append(line[start:i]) 

## -- End pasted text -- 

In [37]: answer 
Out[37]: ['0x04', '0xf']