使用moveToThread在PyQt5中啓動QThreads。一個線程無法正常啓動

我在下面的（半）工作示例中有4個工作線程。我只能讓前三個工作線程工作。我怎樣才能讓第四個線程運行？使用moveToThread在PyQt5中啓動QThreads。一個線程無法正常啓動

print(QThread.idealThreadCount())在我的筆記本電腦上返回'8'。

我可以對代碼進行重新排序以使3個工作人員的任意組合運行。

from PyQt5.QtCore import QThread, QObject 
from PyQt5.QtWidgets import QWidget 
import sys 
from PyQt5.QtWidgets import QApplication 
import time 

class A(QObject): 
    def run(self): 
     while 1: 
      print('A', time.ctime()) 
      time.sleep(1) 
class B(QObject): 
    def run(self): 
     while 1: 
      print('B', time.ctime()) 
      time.sleep(1) 
class C(QObject): 
    def run(self): 
     while 1: 
      print('C', time.ctime()) 
      time.sleep(1) 
class D(QObject): 
    def run(self): 
     while 1: 
      print('D', time.ctime()) 
      time.sleep(1) 

class window1(QWidget): 
    def __init__ (self, parent = None): 
     super().__init__() #parent widget 
     print(QThread.idealThreadCount()) 

     self.thread1 = QThread() 
     obj1 = A() 
     obj1.moveToThread(self.thread1) 
     self.thread1.started.connect(obj1.run) 
     self.thread1.start() 

     self.thread2 = QThread() 
     obj2 = B() 
     obj2.moveToThread(self.thread2) 
     self.thread2.started.connect(obj2.run) 
     self.thread2.start() 

     self.thread3 = QThread() 
     obj3 = C() 
     obj3.moveToThread(self.thread3) 
     self.thread3.started.connect(obj3.run) 
     self.thread3.start() 

     self.thread4 = QThread() 
     obj4 = D() 
     obj4.moveToThread(self.thread4) 
     self.thread4.started.connect(obj4.run) 
     self.thread4.start() 

app = QApplication(sys.argv) 
w = window1() 
w.show() 
sys.exit(app.exec_())

來源

2015-07-13 Ninga

您還沒有存儲參考到obj1，obj2等。作爲它們沒有父（這是需要使用moveToThread）它們處於所述__init__方法結束時收集的垃圾。您添加的time.sleep(1)只會延遲__init__方法的末尾和垃圾回收。

如果您存儲對象的引用（例如self.obj1 = ...），那麼您的所有線程都應該正常運行。

來源

2015-07-13 08:28:11

當然可以！謝謝。 – Ninga

但如果我有很多線程，在將它們存儲在諸如self._threads之類的列表中後，如何在完成後將它們刪除？ – Shuman

@Shuman請[問一個新問題]（http://stackoverflow.com/questions/ask）。這不是真正的拓展地點，答案可能取決於您的具體情況。 –

我想通了，如果我在__init__方法VERT末尾添加time.sleep(1)延遲，所有線程現在的工作....

我想無論如何，瞭解原因。更好的答案將不勝感激。

from PyQt5.QtCore import QThread, QObject 
from PyQt5.QtWidgets import QWidget, QApplication 
import sys 
import time 

class A(QObject): 
    def run(self): 
     while 1: 
      print('A', time.ctime()) 
      time.sleep(1) 
class B(QObject): 
    def run(self): 
     while 1: 
      print('B', time.ctime()) 
      time.sleep(1) 
class C(QObject): 
    def run(self): 
     while 1: 
      print('C', time.ctime()) 
      time.sleep(1) 
class D(QObject): 
    def run(self): 
     while 1: 
      print('D', time.ctime()) 
      time.sleep(1) 

class window1(QWidget): 
    def __init__ (self, parent = None): 
     super().__init__() #parent widget 

     self.thread1 = QThread() 
     obj1 = A() 
     obj1.moveToThread(self.thread1) 
     self.thread1.started.connect(obj1.run) 
     self.thread1.start() 

     self.thread2 = QThread() 
     obj2 = B() 
     obj2.moveToThread(self.thread2) 
     self.thread2.started.connect(obj2.run) #this sets up a signal in the other direction?? 
     self.thread2.start() 

     self.thread3 = QThread() 
     obj3 = C() 
     obj3.moveToThread(self.thread3) 
     self.thread3.started.connect(obj3.run) #this sets up a signal in the other direction?? 
     self.thread3.start() 

     self.thread4 = QThread() 
     obj4 = D() 
     obj4.moveToThread(self.thread4) 
     self.thread4.started.connect(obj4.run) 
     self.thread4.start() 

     time.sleep(1) 

app = QApplication(sys.argv) #every pyqt application must create an application object 
w = window1() 
w.show() 
sys.exit(app.exec_())

來源

2015-07-13 08:19:11 Ninga

使用moveToThread在PyQt5中啓動QThreads。一個線程無法正常啓動

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