運行時錯誤424 ..對象所需

Question

我得到這個錯誤在Microsoft Access：

運行時錯誤424對象所需

而下面是我在後端使用VBA代碼

VBA代碼

Private Sub Command87_Click() 
If Me.phase <> "" Then 
    Me.lst_caseItems.RowSource = " " & _ 
     "SELECT tbl_master.fld_masterID, " & _ 
      "tbl_master.fld_masterActionNo AS ActionNumber, " & _ 
      "tbl_master.fld_masterStudyActionNo AS StudyActionNo, tbl_master.fld_masterIssuedTo," & _ 
      "tbl_master.fld_masterRev AS Rev, tbl_phases.fld_phase AS Phase, tbl_studies.fld_study AS Study, " & _ 
     "FROM ((tbl_master LEFT JOIN tbl_studies ON tbl_master.fld_studyID = ' " & tbl_studies.fld_studyID & " ') LEFT JOIN tbl_phases ON tbl_master.fld_phaseID = ' " & tbl_phases.fld_phaseID & " ') LEFT JOIN tbl_locations ON tbl_master.fld_locationID = ' " & tbl_locations.fld_locationID & " ';" 
End If 
End Sub 

Answer 1

在你當前的代碼，V：一個按鈕BA認爲tbl_studies.fld_studyID是一個變量，因此要求一個對象。

使用您當前的代碼;

' " & tbl_studies.fld_studyID & " ' 

的"關閉SQL語句，那麼你的符號tbl_studies或等告訴VBA在變量tbl_studies.fld_studyID的附加價值，然後與符號後面"重新打開VBA內的SQL語句（等編譯所有的流量爲必要）。由於您沒有名爲studyID的變量，因此它看起來像是您所需對象的原因。

要解決這個問題，您可能需要一個變量分配給您想要的ID（如dim X as long然後x = studyIDyouwanthere）或正確地寫你的查詢，使其鏈接到研究表字段studyID。仔細看看它，看起來你只需要在VBA窗口中正確地編寫查詢，以便它在語法上是正確的（在VBA的解釋中），請嘗試以下內容;

Private Sub Command87_Click() 
If Me.phase <> "" Then 
    Me.lst_caseItems.RowSource = " " & _ 
     "SELECT tbl_master.fld_masterID, " & _ 
      "tbl_master.fld_masterActionNo AS ActionNumber, " & _ 
      "tbl_master.fld_masterStudyActionNo AS StudyActionNo, tbl_master.fld_masterIssuedTo," & _ 
      "tbl_master.fld_masterRev AS Rev, tbl_phases.fld_phase AS Phase, tbl_studies.fld_study AS Study, " & _ 
     "FROM ((tbl_master LEFT JOIN tbl_studies ON tbl_master.fld_studyID = tbl_studies.fld_studyID) LEFT JOIN tbl_phases ON tbl_master.fld_phaseID = tbl_phases.fld_phaseID) LEFT JOIN tbl_locations ON tbl_master.fld_locationID = tbl_locations.fld_locationID;" 
End If 
End Sub 

當您在查詢中加入VBA你不加入基於變量的值，你只能使用他們爲您select部分或having/where/group BY不上加入。