python正則表達式找到單引號內的所有單個行數

Question

你能幫我用正則表達式找到單引號內的所有單引號嗎？

IE

'sinead o'connor','don't don't','whatever' 

感謝您的任何意見。

Answer 1

看起來像你的字符串被逗號隔開。

re.sub(r"\b'\b", "''", s) 

或

(?<=[^,])'(?!,|$) 

DEMO

例子：

>>> import re 
>>> s = "'sinead o'connor','don't don't','whatever'" 
>>> re.sub(r"\b'\b", "''", s) 
"'sinead o''connor','don''t don''t','whatever'" 
>>> 

Answer 2

你可以做到這一點，即使沒有正則表達式：

>>> string = "'sinead o'connor','don't don't','whatever'" 
>>> string = string.replace("'", "''") 
"''sinead o''connor'',''don''t don''t'',''whatever''" 
>>> string.strip("'") 
"sinead o''connor'',''don''t don''t'',''whatever" 

Answer 3

試試這個：

'[\w|\s]*([']*)[\w|\s]*' 

入住這對regex101.com