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在以下情況下,名稱參數與功能發生衝突。名稱參數與功能類型之間的不匹配
鑑於有些系列化基礎設施:
// needs recursive access to itself. for reasons
// beyond the scope of this questions, `self` must
// be a by-name parameter
class Transport(self: => Source[Transport])
// again: self is required to be by-name
def transportSer(self: => Source[Transport]) : Serializer[Transport] =
new Serializer[Transport] {
def read(in: In)(implicit tx: Tx): Transport = new Transport(self)
}
現在想象一個名叫Hook
包裝與遞歸/相互連接性交易:
trait Tx {
def readSource[A](implicit ser: Serializer[A]) : Source[A] =
new Source[A] {
def get(implicit tx: Tx): A = ser.read(new In {})
}
}
trait In
trait Source[A] { def get(implicit tx: Tx): A }
trait Serializer[A] { def read(in: In)(implicit tx: Tx): A }
和示例以及它的串行輸入
trait Hook[A] {
def source: Source[A]
}
及其串行器:
def hookSer[A](peerSelf: Source[A] => Serializer[A]) : Serializer[Hook[A]] =
new Serializer[Hook[A]] {
def read(in: In)(implicit tx: Tx) : Hook[A] =
new Hook[A] with Serializer[A] {
val source: Source[A] = tx.readSource[A](this)
def read(in: In)(implicit tx: Tx) : A = peerSelf(source).read(in)
}
}
那麼下面失敗:
val hs = hookSer[Transport](transportSer)
<console>:15: error: type mismatch;
found : => Source[Transport] => Serializer[Transport]
required: Source[Transport] => Serializer[Transport]
val hs = hookSer[Transport](transportSer)
^
如何這個問題能解決而不改變由名函數的參數(儘可能)?