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下面是一個代碼：錯誤：返回值類型不匹配的功能類型
#include<stdio.h>
#include<math.h>
float conv2D(int rowsKernel, int colsKernel, int rowsImage, int colsImage, float kernel[][5], int image[][15], float imageConvolved[][11]); //Function Prototype definition
float conv2D(int rowsKernel, int colsKernel, int rowsImage, int colsImage, float kernel[][5], int image[][15], float imageConvolved[][11])
{
int kernelSize; //This variable represents the size of the Gaussian kernel
int i; //variable which controls the rows of an image
int j; //variable which controls the columns of an image
int ii; //variable which controls the rows of the kernel
int jj; //variable which controls the columns of the kernel
float sum; //variable that holds the result of convolution for a particular pixel of an image
//float imageConvolved;//Result of an image convolved by a Gaussian kernel
int imagePixel;
float kernelPixel;
kernelSize = colsKernel; /*Since we consider a square kernel, then rowsKernel=colsKernel, which implies that the size of the kernel (kernelSize) equals either of these two variables (that is, kernelSize=colsKernel=rowsKernel) */
for (i = kernelSize/2; i < rowsImage - kernelSize/2; i++) // perform iteration through the rows of an image
{
for (j = kernelSize/2; j < colsImage - kernelSize/2; j++) // perform iteration through the columns of an image
{
sum = 0; /*Initializing the accumulator. This variable will finally contain the convolution result for a particular pixel */
for (ii = -kernelSize/2; ii <= kernelSize/2; ii++) // perform iteration through the rows of a kernel
{
for (jj = -kernelSize/2; jj <= kernelSize/2; jj++) //perform iteration through the columns of a kernel
{
imagePixel = image[i + ii][j + jj];
kernelPixel = kernel[ii + kernelSize/2][jj + kernelSize/2];
sum += imagePixel * kernelPixel;
}
}
imageConvolved[i - kernelSize/2][j - kernelSize/2] = sum;
}
}
return (imageConvolved); // convolved image
}
int main()
{
float gauss[][5] = {
{1, 1, 1, 1, 1},
{1, 1, 1, 1, 1},
{1, 1, 1, 1, 1},
{1, 1, 1, 1, 1},
{1, 1, 1, 1, 1}
};
int img[][15] = {
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1}
};
int rowsK = 5, colsK = 5, rowsI = 15, colsI = 15;
float result[11][11];
float Iconv[11][11];
Iconv = conv2D(rowsK, colsK, rowsI, colsI, gauss, img, result);
return 0;
}
我修改了代碼作爲一種嘗試，試圖解決這個問題。但是，我得到兩個錯誤（使用的CCStudio V3.3）：
"convolution.c", line 39: error: return value type does not match the function type "convolution.c", line 71: error: expression must be a modifiable lvalue
請粘貼**真實代碼**，包括每個參數及其類型的聲明，**作爲代碼**;沒有被埋入一段。你的描述，「這個函數中的參數被聲明爲浮點結果，int rowsK，int colsK，int rowsI和int colsI」，它很容易丟失最後兩個參數類型，如果它不明顯，它們是至關重要的找到你的問題。因此諷刺的是，他們不包括在內。總之，不要只告訴我們「關於」你的代碼; **展示下**。 – WhozCraig
什麼是'imageConvolved'？您可以將它作爲二維數組訪問並將其作爲「float」返回。你要哪個？另外，我同意上述評論。你的問題在眼睛上很難。包含代碼作爲代碼塊，而不是作爲段落內的粗體塊。 – paddy
你說imageConvolved被定義爲float，但是你表現得像2D數組。並且你從返回float的函數返回它，所以它看起來是一個純粹的float值，你試圖用作二維數組..如果你只是複製和粘貼你的代碼可能會更好.. – phoad