如何傳遞參數（NULL）和硬編碼值JOOQ

Question

如果我有它運行在SQL查詢是：

String contactWhere = " UNION SELECT FoldContact.FoldRSN,NULL PeopleRSNCode,'A' FileIndicator from People,Contact" 

但是，我們如何通過NULL PeopleRSNCrypt和'A' FIleIndicator在jooq。如果我們有

SelectQuery<Record> selectQuery = create.selectQuery(); 
     selectQuery.addSelect(Contact.FOLD_CONTACT.FOLD_RSN); 

Answer 1

使用Factory.value("A").as("FIleIndicator")和Factory.inline(null).as("PeopleRSNCrypt")