註冊成功，但不寫信息到數據庫

Question

我有這個問題，註冊是成功的，但它不會將信息寫入數據庫..爲什麼？

註冊過程CODE：

<?php 
include_once 'db_connect.php'; 
include_once 'psl-config.php'; 

$error_msg = ""; 

if (isset($_POST['username'], $_POST['email'], $_POST['p'])) { 
    // Sanitize and validate the data passed in 
    $username = filter_input(INPUT_POST, 'username', FILTER_SANITIZE_STRING); 
    $email = filter_input(INPUT_POST, 'email', FILTER_SANITIZE_EMAIL); 
    $email = filter_var($email, FILTER_VALIDATE_EMAIL); 
    if (!filter_var($email, FILTER_VALIDATE_EMAIL)) { 
     // Not a valid email 
     $error_msg .= '<p class="error">The email address you entered is not valid</p>'; 
    } 


    $password = filter_input(INPUT_POST, 'p', FILTER_SANITIZE_STRING); 

    // Username validity and password validity have been checked client side. 
    // This should should be adequate as nobody gains any advantage from 
    // breaking these rules. 
    // 

    $prep_stmt = "SELECT id FROM members WHERE email = ? LIMIT 1"; 
    $stmt = $mysqli->prepare($prep_stmt); 

    // check existing email 
    if ($stmt) { 
     $stmt->bind_param('s', $email); 
     $stmt->execute(); 
     $stmt->store_result(); 

     if ($stmt->num_rows == 1) { 
    $error_msg .= '<p class="error">A user with this email address already exists.</p>'; 
} 
$stmt->close(); 
    } 
    // check existing username 
    $prep_stmt = "SELECT id FROM members WHERE username = ? LIMIT 1"; 
    $stmt = $mysqli->prepare($prep_stmt); 

    if ($stmt) { 
     $stmt->bind_param('s', $username); 
     $stmt->execute(); 
     $stmt->store_result(); 

       if ($stmt->num_rows == 1) { 
    $error_msg .= '<p class="error">A user with this username already exists.</p>'; 
} 

$stmt->close(); 
    } 

    // TODO: 
    // We'll also have to account for the situation where the user doesn't have 
    // rights to do registration, by checking what type of user is attempting to 
    // perform the operation. 

    if (empty($error_msg)) { 

     // Create salted password 
     $passwordHash = password_hash($password, PASSWORD_BCRYPT); 

     // Insert the new user into the database 
     if ($insert_stmt = $mysqli->prepare("INSERT INTO members (username, email, password) VALUES (?, ?, ?)")) { 
    $insert_stmt->bind_param('sss', '$username', '$email', '$passwordHash'); 
      // Execute the prepared query. 
      if (! $insert_stmt->execute()) { 
       header('Location: ../error.php?err=Registration failure: INSERT'); 
      } 
     } 
     header('Location: ./continue.php'); 
    } 
} 

登記表：

<div class="register-form"> 
    <center><h2>Registration</h2></center> 
     <form action="<?php echo esc_url($_SERVER['PHP_SELF']); ?>" 
       method="post" 
       name="registration_form"> 
      <center><p></p><input type='text' 
       name='username' 
       placeholder="Username" 
       id='username' /><br></center> 
      <center><p></p><input type="text" name="email" id="email" placeholder="Email" /><br></center> 
      <center><p></p><input type="password" 
          name="password" 
          placeholder="Insert Password" 
          id="password"/><br></center> 
      <center><p></p><input type="password" 
            name="confirmpwd" 
            placeholder="Repeat Password" 
            id="confirmpwd" /><br></center> 
      <center><p></p><input type="submit" class="button" 
        value="Register" 
        onclick="return regformhash(this.form, 
            this.form.username, 
            this.form.email, 
            this.form.password, 
            this.form.confirmpwd);" /> </center> 
     </form> 
     </div> 

它做的工作最後一次，但現在並沒有因爲服務器有一個內部錯誤，所以我不得不重新上傳所有文件並創建一個新的數據庫。我重寫了數據庫名稱並傳遞了所有的內容，所以它連接到了正確的數據庫，但它在註冊時不會將信息寫入該數據庫。

Answer 1

您正在插入文字字符串，您的變量名稱，而不是值。

$insert_stmt->bind_param('sss', '$username', '$email', '$passwordHash'); 

您需要：

$insert_stmt->bind_param('sss', $username, $email, $passwordHash);