檢索所有的用戶（用戶ID和用戶名）

Question

我想要檢索的所有用戶在我的數據庫，並把它們與兩個元素的數組;一個包含一個包含所有用戶標識的數組，另一個包含所有用戶名的數組。但是，下面的代碼不適用於此目的。它的作用是將第一個用戶放入$ field1（第一個用戶的用戶標識）和$ field2（第一個用戶的用戶名）中。

我需要如何解決這個問題的幫助。

基本上，我要的是實現以下目標：

$userIds = array(1, 2, 3, 4, 5); // The id's from all users in an array 
$userNames = array("Nisse", "Kalle", "Svenne", "Jonna", "Linda"); // The usernames of all the users in an array 

// The arrays with user id's and usernames should be put in a new array that's returned from the function. 
$users = array(
    [0] => $userIds, 
    [1] => $userNames 
); 

從UserHandler.php：

class UserHandler { 

    private $m_db = null; 

    public function __construct(Database $db) { 
     $this->m_db = $db; 
    } 

    public function GetAllUsers() { 

     $userArray = array(); 

     $query = 'SELECT * FROM Users'; 

     $stmt = $this->m_db->Prepare($query); 

     $userArray = $this->m_db->GetUsers($stmt); 

     return $userArray; 
    } 
} 

從database.php中：

public function GetUsers(\mysqli_stmt $stmt) { 
     $userArray = array(); 

     if ($stmt === FALSE) { 
       throw new \Exception($this->mysqli->error); 
     } 

     //execute the statement 
     if ($stmt->execute() == FALSE) { 
       throw new \Exception($this->mysqli->error); 
     } 
     $ret = 0; 

     if ($stmt->bind_result($field1, $field2, $field3) == FALSE) { 
      throw new \Exception($this->mysqli->error); 
     } 

     $stmt->fetch(); 

     $stmt->Close(); 

     echo $field1 // "1"; <- userid of the first user in db table 
     echo $field2 // "Kalle" <- username of the first user in the db table 

     $userArray[] = $field1; // An array with all the user id's 
     $userArray[] = $field2; // An array with all the usernames 

     return $userArray; 
} 

db表看起來像這樣： userId |用戶名|密碼

Answer 1

做$stmt->fetch()只有一次你只取從結果表的第一行，所以你需要對結果表中的循環：

public function GetUsers(\mysqli_stmt $stmt) { 
    $userArray = array(
     0 => array(), 
     1 => array() 
    ); 

    // the rest of code is the same here 

    // replace the line $stmt->fetch() with this block 
    while ($stmt->fetch()) { 
     array_push($userArray[0], $field1); 
     array_push($userArray[1], $field2); 
    } 

    // remove these lines 
    /* 
    $userArray[] = $field1; 
    $userArray[] = $field2; 
    */ 

    return $userArray 
}