計劃「日」，75％的工作...幫助JAVA

Question

我的代碼

75％的作品，這部分工作正常，我的任務......我已經得到了部分洛根。

它下面我不能運行與該部分的代碼...

• F.計算並返回當天 一天添加某些天的一天。例如，如果當天是星期一，並且我們添加了四天，則要返回的日期是星期五。同樣，如果今天是星期二，並且 我們增加13天，則返回的日期是星期一。 G.添加適當的構造函數。

任何建議如何我可以構造我寫的，以得到它與第一部分計算？

import java.util.*; 
/* 
Personal information 
*/ 
public class MyDayIIII 
{ 
static Scanner readinput = new Scanner(System.in); //Creates common input object class 
String d1;          // Private member variable 

public MyDayIIII(String d1)    //Constructor of value Sunday 
{ 
d1 = "Sunday"; 
} 
public void setD1(String theD1)   //Assigns value for user's input for "set day" 
{ 
d1 = theD1; 
} 
public String claimD1()     //Displays user's day 
{ 
return d1; 
} 
// print the day, looks unnecessary 
public void printD1() 
{ 
System.out.println("Printed Day: " + d1); 
} 
// return the next day 
public String tomD1() 
{ 



// using direct comparison will fail as day == "Saturday"? 
// so use compareTo() method... 
if(d1.compareTo("Saturday") == 0) 
return ("Sunday"); 
else if(d1.compareTo("Sunday") == 0) 
return ("Monday"); 
else if(d1.compareTo("Monday") == 0) 
return ("Tuesday"); 
else if(d1.compareTo("Tuesday") == 0) 
return ("Wednesday"); 
else if(d1.compareTo("Wednesday") == 0) 
return ("Thursday"); 
else if(d1.compareTo("Thursday") == 0) 
return ("Friday"); 
else if(d1.compareTo("Friday") == 0) 
return ("Saturday"); 
else 
return ("\"Please Capitalize the First Letter of Your Day(e.g. Monday)\""); 
} 
// return the previous day 
public String SetprD1() 
{ 
if(d1.compareTo("Friday") == 0) 
return ("Thursday"); 
else if(d1.compareTo("Thursday") == 0) 
return ("Wednesday"); 
else if(d1.compareTo("Wednesday") == 0) 
return ("Tuesday"); 
else if(d1.compareTo("Tuesday") == 0) 
return ("Monday"); 
else if(d1.compareTo("Monday") == 0) 
return ("Sunday"); 
else if(d1.compareTo("Sunday") == 0) 
return ("Saturday"); 
else if(d1.compareTo("Saturday") == 0) 
return ("Friday"); 
else 
return ("\"Please Capitalize the First Letter of Your Day(e.g. Monday)\""); 
} 

public static void main (String args[]) 
{ 
MyDay testday = new MyDay("Sun"); 
System.out.print("Enter A Day(First Letter Capitalized & Full Spelling) "); 
// read and store user's day 
String storeday = readinput.nextLine(); 
// invoke setDay() method to set a day defined by user 
testday.setDay(storeday); 
// invoke getDay() method to get a day 
System.out.println("You Chose: " + testday.getDay()); 
// test printing by invoking printDay() method 
testday.printDay(); 
// invoke getPreDay() method to get the previous day 
System.out.println("Day Prior Is: " + testday.getPreDay()); 
// invoke getNextDay() method to get the next day 
System.out.println("The Following Day Is: " + testday.getNextDay()); 
} 
} 

我一直試圖插入這一點，把它做兼職F.

這將啓動，但我得到以下...

at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48) 
    at java.lang.Integer.parseInt(Integer.java:449) 
    at java.lang.Integer.valueOf(Integer.java:554) 
    at TextCalculator.main(TextCalculator.java:24 

所以我把它拿出來，中原來......誰能給我任何意見，我感到沮喪...

我的目標是創建7個元素的數組，然後用7:3的係數計算未來的日期，並把它對應以元素的價值...

String[] day = new String[7]; 

day[0] = "Monday";     //Elements were assigned the day of the week for their value 
day[1] = "Tuesday"; 
day[2] = "Wendesday"; 
day[3] = "Thursday"; 
day[4] = "Friday"; 
day[5] = "Saturday"; 
day[6] = "Sunday"; 

Scanner scanner = new Scanner(System.in); 

System.out.println("Enter a Number for Future Days:");  //Prompting user to input number of days 

String future = scanner.nextLine(); 

int futureDay = Integer.valueOf("future"); 

int numDay = day.length % 7;  //Using value of elements, with modulus 7 to assign value  and determine placement 

while (numDay >= day.length)  
{ 
numDay -= day.length; 
} 

Answer 1

看起來像你的代碼說

int futureDay = Integer.valueOf("future"); 

當它應該是

int futureDay = Integer.valueOf(future); 

注意周圍的未來暫無報價。這是因爲「future」是一個帶有字符f，u，t，u，r，e（並且顯然不是整數）的字符串，其中future是您之前聲明的變量的名稱。