嘿我試圖找出嵌套循環的增長率,我知道第一個循環將會運行100次,因爲它只能運行100次,但第二循環我不太確定。 任何人都可以幫助我?這些循環可以執行多少次?
29 for (int i = 0; i < MAX; ++i)
30 {
31 for (int j = 0; m[i] < m[j] && m[j] != 0; ++j)
32 {
33 product = product + (m[i] * n[j]);
34 }
35 }
完整的代碼是在這裏
01 const int MAX = 100;
02 int lowerCount;
03 int higherCount;
04 int equalCount;
05 int product;
06
07 lowerCount = higherCount = equalCount = 0;
08 product = 0;
09
10 for (int i = 0; i < MAX; i++)
11 {
12 if (m[i] < n[i])
13 {
14 ++higherCount;
15 }
16 else
17 {
18 if (m[i] == n[i])
19 {
20 ++lowerCount;
21 }
22 else
23 {
24 ++equalCount;
25 }
26 }
27 }
28
29 for (int i = 0; i < MAX; i++)
30 {
31 for (int j = 0; m[i] < m[j] && m[j] != 0; j++)
32 {
33 product = product + (m[i] * n[j]);
34 }
35 }
36
37 cout << "lowerCount " << lowerCount << "\n";
38 cout << "equalCount " << equalCount << "\n";`
39 cout << "higherCount " << higherCount << "\n";
40 cout << "product " << product << "\n"";
我的魔球沒有顯示m [i]和m [j]的值:( – 2013-04-24 13:22:00
我只需要計算增長率,我沒有m [i]和m [ j]對不起:( – 2013-04-24 13:24:18
希望你找到正確的答案,除此之外;) – 2013-04-24 13:31:51