SUM每月

Question

總的我有這個表有兩列：

Price  Date 
45.00  12/06/2015 12:32:54 AM 
455.98  22/06/2015 11:00:32 AM 
32.00  08/07/2015 09:11:45 AM 
98.00  11/07/2015 19:22:32 PM 

（日期格式爲DD/MM/YYYY）

我需要得到價格的總和按月分組，爲此，我需要在sqlite中找到一個代碼，以便僅在該月份（06 ...）（... 07 ...）中刪除該日期的某些部分。以下是我的代碼用於選擇某些部分：

SELECT SUM(CAST(price as INTEGER)) as TOTALPERMONTH FROM cart_history GROUP BY ....... ORDER BY ID 

我怎麼可以按該行的某些部分分組？

Answer 1

使用STRFTIME功能

select SUM(CAST(price as INTEGER)) as Total, 
     strftime('%m', dateField) as Month 
From yourtable 
Group by strftime('%m', dateField) 

Answer 2

使用HAVING條款。

SELECT SUM(CAST(price as INTEGER)) as TOTALPERMONTH 
FROM cart_history,Date 
GROUP BY Date 
HAVING Date IN('your dates ')'