c＃需要通過向兩個方向移動對象來提供幫助

Question

我需要通過在兩個不同方向上移動Panel上的對象來獲得幫助。例如，通過按下右側和左側按鈕在右側和下方向。 Java有一個關鍵的發佈方法嗎c＃有這樣一個類似的方法嗎？

using System; 
using System.Collections.Generic; 
using System.ComponentModel; 
using System.Data; 
using System.Drawing; 
using System.Linq; 
using System.Text; 
using System.Threading.Tasks; 
using System.Windows.Forms; 

namespace runningRectangle 
{ 
    enum Position {Left, Right, Down, Up, LeftUp, LeftDown, RightUp, RightDown } 
    public partial class Form1 : Form 
    { 
     private int x; 
     private int y; 
     private Position objPos; 
     private int speed = 10; 
     private bool stopPressed = false; 

    public Form1() 
    { 
    InitializeComponent(); 
     x = 50; 
     y = 50; 


    } 

private void Form1_Paint(object sender, PaintEventArgs e) 
    { 
     e.Graphics.FillRectangle(Brushes.Red, x, y, 50, 50); 
    } 

    private void timer1_Tick(object sender, EventArgs e) 
    { 
     if(objPos == Position.Right) 
     { 
      x += speed; 

     }else if(objPos == Position.Left) 
     { 
      x -= speed; 
     } 
     else if (objPos == Position.Down) 
     { 
      y += speed; 
     } 
     else if (objPos == Position.Up) 
     { 
      y -= speed; 
     } else if (objPos == Position.RightUp) 
     { 
      x += speed; 
      y -= speed; 
     } 
     else if (objPos == Position.RightDown) 
     { 
      x += speed; 
      y += speed; 
     } 
     else if (objPos == Position.LeftUp) 
     { 
      x -= speed; 
      y += speed; 
     } 
     else if (objPos == Position.LeftDown) 
     { 
      x -= speed; 
      y -= speed; 
     } 

     Invalidate(); 
    } 
    private void Form1_KeyDown(object sender, KeyEventArgs e) 
    { 
      if (e.KeyCode == Keys.Right) 
      { 
      objPos = Position.Right; 

      } 

      else if (e.KeyCode == Keys.Left) 
      { 
      objPos = Position.Left; 

     } 
      else if (e.KeyCode == Keys.Down) 
      { 
      objPos = Position.Down; 

     } 
      else if (e.KeyCode == Keys.Up) 
      { 
      objPos = Position.Up; 
     } 
     else if(e.KeyCode == Keys.Right && e.KeyCode == Keys.Down) 
     { 
      objPos = Position.RightDown; 
     } 
     else if (e.KeyCode == Keys.Right && e.KeyCode == Keys.Up) 
     { 
      objPos = Position.RightUp; 
     } 
     else if (e.KeyCode == Keys.Left && e.KeyCode == Keys.Down) 
     { 
      objPos = Position.LeftDown; 
     } 
     else if (e.KeyCode == Keys.Left && e.KeyCode == Keys.Up) 
     { 
      objPos = Position.LeftUp; 

     } 

     else if(e.KeyCode == Keys.Space) 
     { 
      if (!stopPressed) 
      { 
       speed = 0; 
       stopPressed = true; 
      } 
      else if(stopPressed) 
      { 
       speed += 10; 
       stopPressed = false; 
      } 
     }   
     } 
} 
} 

Answer 1

Form1_KeyDown和​​存在對。

enum Position { None = -1, Left, Right, Down, Up, LeftUp, LeftDown, RightUp, RightDown } 

private void Form1_KeyUp(object sender, KeyEventArgs e) 
{ 
    objPos = (Position)(-1); 
}