在java中使用數組

Question

所以我正在處理java中的數組，並且遇到了一個問題，我試圖列出f中長度爲100的數組中最少出現數的位置，範圍爲0-9。我正在使用第二個數組來計算出現次數，直到我的最後一段代碼才完成。

import java.util.Random; 

public class Program6 
{ 
public static void main(String[] args) 
{ 
    int[] bigArray = new int[100]; 
    int[] count = new int[10]; 


    for (int i = 0; i < bigArray.length ;i++) 
     { 
      bigArray[i] = (int)(Math.random() * 10);  
     } 
    for (int i = 0; i < bigArray.length ;i++) 
     { 
      System.out.println(bigArray[i] + " "); 
     } 
    for(int i = 0; i < bigArray.length; i++) 
     { 
      count[bigArray[i]]++; 
     } 



    for (int i = 0, j = 0; i < count.length ;i++, j++) 
      System.out.println("count for " + j +" is: " + count[i] + " "); 

    int min = count[0]; 
    int indexOfMin = 0; 

    for (int i =1; i < count.length; i++) 
     { if (count[i] < min) 
       { 
        min = count[i]; 
        indexOfMin = i; 
       } 
     } 

    System.out.println("\nThe number " + indexOfMin + " only appears " + min + " times in the array."); 
    System.out.println("It appears in the large array at: "); 

    \\this guy right here 
    for (int i = 0 ; i < bigArray.length; i++) 
     { if (bigArray[i] == min) 
       { 
        System.out.println("bigArray["+ i + "]"); 

       } 
     } 

} 

}

應該只列出關閉陣列的位置。但它返回的方式不僅僅是最低出現整數的位置，即使限定符使用變量分鐘。

什麼給？我錯過了什麼？

沒有輸入，即返回輸出是

8 
.. 
4 
count for 0 is: 18 
count for 1 is: 6 
count for 2 is: 9 
count for 3 is: 9 
count for 4 is: 16 
count for 5 is: 4 
count for 6 is: 12 
count for 7 is: 8 
count for 8 is: 7 
count for 9 is: 11  

The number 5 only appears 4 times in the array. 
It appears in the large array at: 
bigArray[3] 
bigArray[6] 
bigArray[10] 
bigArray[23] 
bigArray[25] 
bigArray[39] 
bigArray[44] 
bigArray[48] 
bigArray[49] 
bigArray[50] 
bigArray[51] 
bigArray[57] 
bigArray[58] 
bigArray[67] 
bigArray[84] 
bigArray[99] 

這是完美的，除了bigArray []列表輸出。它應該只顯示索引何時數組等於最少出現的數字。

Answer 1

您正在比較數字的數量。改用號碼。更新

//this guy right here 
for (int i = 0 ; i < bigArray.length; i++) 
    { if (bigArray[i] == min) 
      { 
       System.out.println("bigArray["+ i + "]"); 

      } 
    } 

使用indexOfMin作爲

`//this guy right here 
for (int i = 0 ; i < bigArray.length; i++) 
    { if (bigArray[i] == indexOfMin) 
      { 
       System.out.println("bigArray["+ i + "]"); 

      } 
    }