如何發佈一個變量在ajax調用多個php文件？

Question

如何發佈在Ajax調用多個PHP文件的使用URL方法，一個變量.. 我的數據是遵循..

<select name="districts" id="district_list" class="update" onChange="getDist(this.value)" > 
    <option value="d1">east</option> 
    <option value="d2">west</option>   
</select> 

我想用ajax傳遞價值，另外兩個PHP文件這些ID和我嘗試如下..

function getState(val) { 

    $.ajax({ 
    type: "POST", 
    url: "get_dist.php", 
    url: "get_city.php",  
    data:'states_id='+val, 
    success: function(data){    
     $("#district_list").html(data); 
    } 
    }); 

} 

Answer 1

請試試這個

<select name="districts" id="district_list" class="update" onChange="getDist(this.value) ; getCity(this.value)" > 
    <option value="d1">east</option> 
    <option value="d2">west</option> 
</select> 

    <script> 

    function getDist(val){ 
     $.ajax({ 
      type: "POST", 
      url: "get_dist.php", 
      data:'states_id='+val, 
      success: function(data){ 
      $("#district_list").html(data); 
      } 
     }); 
    } 

    function getCity(val){ 
     $.ajax({ 
      type: "POST", 
      url: "get_city.php",  
      data:'states_id='+val, 
      success: function(data){ 
      $("#city_list").html(data); 
      } 
     }); 
    } 
    </script>