想知道如何使用select插入

INSERT INTO report (server_id, reported_id, reporting_id, admin_id) 
      SELECT s.server_id, rep.reported_id, ru.reporting_id, a.admin_id 
      FROM server s, reported_user rep, reporting_user ru, admin a 
      WHERE s.server_port = 'port' 
      AND rep.reported_steam_id = 'id' 
      AND ru.reporting_steam_id = 'id' 
      AND a.admin_id = '0'

正如您在上面看到的，我有一個查詢從其他表中提取信息並將其插入到名爲report的表中。我的問題是，原因是不是外鍵，我不知道如何使查詢與讓說：想知道如何使用select插入

INSERT INTO report (server_id, reported_id, reporting_id, admin_id, reason) 
      SELECT s.server_id, rep.reported_id, ru.reporting_id, a.admin_id 
      FROM server s, reported_user rep, reporting_user ru, admin a 
      WHERE s.server_port = 'port' 
      AND rep.reported_steam_id = 'id' 
      AND ru.reporting_steam_id = 'id' 
      AND a.admin_id = '0', 
      "TEST"; // <-- Does not work. Trying to insert a text string here.

來源

2016-01-21 Perelan

爲'reason'你想添加的「測試」串吧？？ –

這是正確的。所有（server_id，reported_id，reporting_id和admin_id）是對其他表的引用，但「reason」不是。那是一個塔內的「報告」 – Perelan

試試這個

 INSERT INTO report (server_id, reported_id, reporting_id, admin_id, reason) 
     SELECT s.server_id, rep.reported_id, ru.reporting_id, a.admin_id,"TEST" 
     FROM server s, reported_user rep, reporting_user ru, admin a 
     WHERE s.server_port = 'port' 
     AND rep.reported_steam_id = 'id' 
     AND ru.reporting_steam_id = 'id' 
     AND a.admin_id = '0'

來源

2016-01-21 17:36:59

Thansk，只是想通了！這是對的：） – Perelan

想知道如何使用select插入

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