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我有如下的詞典列表:找到共同的關鍵:在字典值對非可哈希鍵和值
[{'EchoTime': 0,
'FlipAngle': 90,
'MRAcquisitionType': '2D',
'MagneticFieldStrength': 3,
'Manufacturer': 'SIEMENS',
'ManufacturerModelName': 'TrioTim',
'RepetitionTime': 2,
'ScanOptions': 'FS',
'ScanningSequence': 'EP',
'SequenceName': 'epfid2d1_64',
'SequenceVariant': 'SK',
'SliceTiming': [[0.0025000000000000022],
[0.5],
[-0.030000000000000027],
[0.46625],
[0.168749999995],
[-0.36124999999999996],
[-0.46124999999500005],
[0.036250000005000005]],
'TaskName': 'tom'},
{'EchoTime': 0,
'FlipAngle': 90,
'MRAcquisitionType': '2D',
'MagneticFieldStrength': 3,
'Manufacturer': 'SIEMENS',
'ScanningSequence': 'EP',
'SequenceName': 'epfid2d1_64',
'SequenceVariant': 'SK',
'SliceTiming': [[0.0037500000050000315],
[0.5],
[-0.030000000000000027],
[0.46750000001500003],
[-0.0625],
[0.36750000001],
[-0.16249999998999998],
[0.33500000000499996],
[-0.19499999998999995],
[0.301250000005]],
'TaskName': 'tom'},
{'EchoTime': 0,
'FlipAngle': 90,
'MRAcquisitionType': '2D',
'MagneticFieldStrength': 3,
'RepetitionTime': 2,
'ScanOptions': 'FS',
'ScanningSequence': 'EP',
'SequenceName': 'epfid2d1_64',
'SequenceVariant': 'SK',
'SliceTiming': [[0.0025000000000000022],
[0.5],
[-0.030000000000000027],
[0.46625],
[-0.19625000000000004],
[0.301250000005],
[-0.22875],
[0.26749999999999996],
[-0.26249999999500007]],
'TaskName': 't1'},
{'EchoTime': 0,
'FlipAngle': 90,
'MRAcquisitionType': '2D',
'Manufacturer': 'SIEMENS',
'ManufacturerModelName': 'TrioTim',
'SequenceVariant': 'SK',
'SliceTiming': [[0.0025000000000000022],
[0.5],
[-0.030000000000000027],
[0.46625],
[-0.06374999999999997],
[0.43375000000499997],
[-0.09624999999999995],
[0.4],
[-0.22875],
[0.26749999999999996],
[-0.26249999999500007],
[0.235]],
'TaskName': 'fb'}]
有列表中的約2000字典。 現在我想在列表中的所有字典中找到公用密鑰:值對。 出於同樣的,我用下面的函數:
def twodict_intersec(json1, json2):
d = {x:json1[x] for x in json1 if x in json2}
return d
for i in range(0,10,1):
print(i)
if i == 0:
res = twodict_intersec(json_list[i], json_list[i+1])
else:
res = dict_intersect(res, json_list[i+1])
print(res)
但輸出是一樣的東西下面,每個鍵包含所有值的列表,而不是共同的價值
res = {'EchoTime': [[[[[[[[[0, 0], 0], 0], 0], 0], 0], 0], 0], 0], 'FlipAngle': [[[[[[[[[90, 90], 90], 90], 90], 90], 90], 90], 90], 90], 'ManufacturerModelName': [[[[[[[[['TrioTim', 'TrioTim'], 'TrioTim'], 'TrioTim'], 'TrioTim'], 'TrioTim'], 'TrioTim'], 'TrioTim'], 'TrioTim']}
我不能夠得到輸出,其中每個關鍵字只有一個在所有詞典中通用的值,而不是上面的情況。有人能指出我的錯誤嗎?
你的意思是我需要用這個'result'我從上面的功能得到我? – learnningprogramming
它不起作用 – learnningprogramming
更新了我的答案。請記住註冊並標記爲解決方案,這對您有很大的幫助。 – Neil