無效的列名稱vehicle_userId「：異常線程「main」 org.hibernate.exception.SQLGrammarException：無法執行語句

Question

package model; 

    import java.util.Date; 

import javax.persistence.Column; 
import javax.persistence.Entity; 
import javax.persistence.GeneratedValue; 
import javax.persistence.GenerationType; 
import javax.persistence.Id; 
import javax.persistence.OneToOne; 
import javax.persistence.Table; 
import javax.persistence.Temporal; 
import javax.persistence.TemporalType; 

@Entity 
@Table(name = "USERDETAILS") 
public class UserDetails { 
    private int userId; 
    private String userName; 
    private Date joineddate; 
    private String description; 
    private Vehicle vehicle; 

    @OneToOne 
    public Vehicle getVehicle() { 
     return vehicle; 
    } 


    public void setVehicle(Vehicle vehicle) { 
     this.vehicle = vehicle; 
    } 


    public void setJoineddate(Date joineddate) { 
     this.joineddate = joineddate; 
    } 


    @Temporal(TemporalType.DATE) 
    public Date getJoineddate() { 
     return joineddate; 
    } 

    public String getDescription() { 
     return description; 
    } 

    public void setDescription(String description) { 
     this.description = description; 
    } 

    @Id 
    @GeneratedValue(strategy=GenerationType.AUTO) 
    public int getUserId() { 
     return userId; 
    } 

    public void setUserId(int userId) { 
     this.userId = userId; 
    } 

    @Column(name = "User_Name") 
    public String getUserName() { 
     return userName; 
    } 

    public void setUserName(String userName) { 
     this.userName = userName; 
    } 
} 

在這裏，我創建的UserDetails表

package model; 

    import javax.persistence.Column; 
    import javax.persistence.Entity; 
    import javax.persistence.GeneratedValue; 
    import javax.persistence.GenerationType; 
    import javax.persistence.Id; 

    @Entity 
    public class Vehicle { 
     private int vehicleId; 
     private String vehicleName; 

     @Id 
     @GeneratedValue(strategy = GenerationType.AUTO) 
     @Column(name="userId") 
     public int getVehicleId() { 
      return vehicleId; 
     } 

     public void setVehicleId(int vehicleId) { 
      this.vehicleId = vehicleId; 
     } 

     public String getVehicleName() { 
      return vehicleName; 
     } 

     public void setVehicleName(String vehicleName) { 
      this.vehicleName = vehicleName; 
     } 

    } 

我在這裏創建汽車表採用一對一的映射

package hibernate; 

import java.util.Date; 

import org.hibernate.Session; 
import org.hibernate.SessionFactory; 
import org.hibernate.cfg.Configuration; 

//import model.Address; 
import model.UserDetails; 
import model.Vehicle; 

public class HibernateTest { 

    public static void main(String[] args) { 
     SessionFactory sessionFactory = new Configuration().configure() 
       .buildSessionFactory(); 
     Session session = sessionFactory.openSession(); 

     UserDetails user = new UserDetails(); 
     user.setUserName("bhagyasri"); 
     user.setDescription("bhagyasri's description"); 
     user.setJoineddate(new Date()); 

     Vehicle vehicle = new Vehicle(); 
     vehicle.setVehicleName("hero"); 

     user.setVehicle(vehicle); 

     session.beginTransaction(); 
     session.save(user); 
     session.save(vehicle); 

     session.getTransaction().commit(); 
     session.close(); 
    } 

} 

我收到錯誤這樣

Jan 16, 2015 4:17:43 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions 
WARN: SQL Error: 207, SQLState: S0001 
Jan 16, 2015 4:17:43 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions 
ERROR: Invalid column name 'vehicle_userId'. 
Exception in thread "main" org.hibernate.exception.SQLGrammarException: could not execute statement 
    at org.hibernate.exception.internal.SQLStateConversionDelegate.convert(SQLStateConversionDelegate.java:123) 
    at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49) 
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126) 
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112) 
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:211) 

Hibernate配置

<?xml version='1.0' encoding='UTF-8'?> 
<!DOCTYPE hibernate-configuration PUBLIC 
      "-//Hibernate/Hibernate Configuration DTD 3.0//EN" 
      "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd"> 

<hibernate-configuration> 

    <session-factory> 
     <property name="hbm2ddl.auto">create</property> 
     <property name="dialect">org.hibernate.dialect.SQLServer2008Dialect</property> 
     <property name="connection.url">jdbc:sqlserver://192.168.2.219\SQLEXPRESS;databaseName=train</property> 
     <property name="connection.username">train</property> 
     <property name="connection.password">tspl@123</property> 
     <property name="connection.driver_class">com.microsoft.sqlserver.jdbc.SQLServerDriver</property> 
     <property name="show_sql">true</property> 
     <mapping class="model.UserDetails" /> 
     <mapping class="model.Vehicle" /> 

    </session-factory> 

</hibernate-configuration> 

，這是我的配置文件..我收到無效的列名稱vehicle_userId「：SQLGrammarException我沒有得到什麼確切的問題有什麼建議？

Answer 1

當你只是把@OneToOne一些映射（vehicle你的情況），則默認預期的列名是<field_name>_<target_id_column_name>而你的情況解析到vehicle_userId，因爲字段名是vehicle和你有Vehicle#getVehicleId()@Column(name="userId")。

首先，vehicleId的列可能是錯誤的（因爲它被命名爲用戶 Id）。所以，改變以

@Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Column(name="vehicleId") 
    public int getVehicleId() { 
     return vehicleId; 
    } 

和UserDetails改變這種

@OneToOne 
@JoinColumn(name = "vehicle_id") 
public Vehicle getVehicle() { 
    return vehicle; 
} 

此，如果你有列USERDETAILS.VEHICLE_ID會工作。