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我想分析Json
響應:如何從HttpResponse對象解析JSON數據
client = new DefaultHttpClient();
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);
任何建議如何做到這一點?
我想分析Json
響應:如何從HttpResponse對象解析JSON數據
client = new DefaultHttpClient();
HttpGet request = new HttpGet(url);
HttpResponse response = client.execute(request);
任何建議如何做到這一點?
您可以使用JSON-簡單
https://code.google.com/p/json-simple/
如果你用maven
<dependency>
<groupId>com.googlecode.json-simple</groupId>
<artifactId>json-simple</artifactId>
<version>1.1</version>
</dependency>
然後在你的代碼
JSONParser jsonParser = new JSONParser();
JSONObject jsonObject = (JSONObject) jsonParser.parse(reader);
// get a String from the JSON object
String firstName = (String) jsonObject.get("firstname");
System.out.println("The first name is: " + firstName);
在這裏有一個例子
http://examples.javacodegeeks.com/core-java/json/java-json-parser-example/
可能的重複[如何從Java HTTPResponse解析JSON?](http://stackoverflow.com/questions/2845599/how-do-i-parse-json-from-a-java-httpresponse ) – Raf