顯示指向個人記錄的鏈接

Question

如何在點擊名稱「Alex」時顯示單個記錄。

<?php 
    echo "<table class='tableSection' border='1'><thead><tr><th><span class='tb_row2'>Referee</span></th><th><span class='tb_row2'>Date Referred</span></th><th><span class='tb_row2'>Status</span></th><th><span class='tb_row2'>Date Approved</span></th></tr></thead>"; 
    $printlist_sql = "select a.Name, a.todate from table1 a left join admin_login b on a.StaffID = b.User_Id where b.Admin_Id ='userID' order by table_Id";  

    echo "<tbody>"; 
      $referral_result = mysql_query($printlist_sql, $link); 
            while ($s_referral_row = mysql_fetch_array($referral_result)) 
            {          
             echo "<tr><td class='tb_row2'>".$s_referral_row['Name']."</td>"; 
             echo "<td class='tb_row2'>".$s_referral_row['todate']."</td>";          
            } 

     echo " </tbody>"; 
    echo "</table>"; 
    ?> 

我的表：

Name Todate 
Alex 2015-05-22 
Alice 2015-05-22 

Answer 1

<?php 
    echo "<table class='tableSection' border='1'><thead><tr><th><span class='tb_row2'>Referee</span></th><th><span class='tb_row2'>Date Referred</span></th><th><span class='tb_row2'>Status</span></th><th><span class='tb_row2'>Date Approved</span></th></tr></thead>"; 
    $printlist_sql = "select a.Name, a.todate from table1 a left join admin_login b on a.StaffID = b.User_Id where b.Admin_Id ='userID' order by table_Id";  

    echo "<tbody>"; 
      $referral_result = mysql_query($printlist_sql, $link); 
            while ($s_referral_row = mysql_fetch_array($referral_result)) 
            {          
             echo "<tr><td class='tb_row2'><a href="test.php">".$s_referral_row['Name']."</a></td>"; 
             echo "<td class='tb_row2'>".$s_referral_row['todate']."</td>";          
            } 

     echo " </tbody>"; 
    echo "</table>"; 
    ?>