2017-07-06 63 views
1

變量'lvl'是IntervalIndex類型,如下所示。如何在IntervalIndex中獲得一些價值?

lvl = IntervalIndex([(1.418, 1.69], (1.69, 6.696], (6.696, 7.217], (7.217, 7.845], (7.845, 10.11] ... (17.648, 18.199], (18.199, 19.315], (19.315, 20.16], (20.16, 22.471], (22.471, 25.009]] 
      closed='right', 
      dtype='interval[float64]') 

現在我已經嘗試添加一些指標值是這樣的:

for each in val_list: 
    for k in range(len(lvl)): 
     lower_val = float(lvl[k][1:-1].split(',')[0]) 
     upper_val = float(lvl[k][1:-1].split(',')[-1]) 
     if each >=lower_val and each <= upper_val: 
      some_var_index.append(k) 

但是,錯誤養我...:

{TypeError}'pandas._libs.interval.Interval' object is not subscriptable 

我如何呢? 謝謝

回答

1

對象是不標化意味着它不會表現得像普通的名單,但你在這裏兩次做它:與第二方括號[1:-1]

lower_val = float(lvl[k][1:-1].split(',')[0]) 
upper_val = float(lvl[k][1:-1].split(',')[-1]) 

。相反,這兩條線使用這一個:

lower_val, upper_val = lvl[k].left, lvl[k].right 

你應該是好的。

+0

謝謝soooooo,Mkos! –