如何在android中的textview上隨機生成24個字符串值？

Question

我想在24個textview上生成24個字符串值，我在android中創建了xml文件，並且我爲getid和set listener編碼，但這裏沒有提到。 在覆蓋oncick方法我定義點擊樂趣的方法。 在這段代碼中，我簡單地爲整數值編碼，但現在我想從具有靜態值的字符串數組中進行比較，如 String [] value = {11,12,13,14,15,16,17,18， 19,20,21,22,11,12,13,14,15,16,17,18,19,20,21,22}; 請幫我解決我的問題。

public class GameDemo extends Activity implements AnimationListener, OnClickListener 
{ 
    FrameLayout iv1,iv2,iv3,iv4,iv5,iv6,iv7,iv8,iv9,iv10,iv11,iv12,iv13,iv14,iv15,iv16,iv17,iv18,iv19,iv20,iv21,iv22,iv23,iv24; 
    TextView tv1,tv2,tv3,tv4,tv5,tv6,tv7,tv8,tv9,tv10,tv11,tv12,tv13,tv14,tv15,tv16,tv17,tv18,tv19,tv20,tv21,tv22,tv23,tv24; 
    Animation an1,an2; 
    int i1,counter,score,rev_count,level_counter; 
    boolean r_c,s_c; 
    Integer[] no; 
    FrameLayout[] count,rem,revise; 
    final Context context = this; 
    @Override 
    protected void onCreate(Bundle savedInstanceState) 
    { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_game_demo); 
    an1 = AnimationUtils.loadAnimation(this,R.anim.flip1); 
    an1.setAnimationListener(this); 
    an2 = AnimationUtils.loadAnimation(this,R.anim.flip1); 
    an2.setAnimationListener(this); 
    level_counter=24; 
    getIDForAll(); 
    setListnerForAll(); 
    counter=1; 
    rev_count=0; 
    no = new Integer[25]; 
      count = new FrameLayout[3]; 
    rem = new FrameLayout[3]; 
    revise = new FrameLayout[8]; 
    int i=0; 
    for(i=0 ; i<24 ; i++) 
    { 
     Random r = new Random(); 
     i1 = r.nextInt(25 - 1) + 1; 
     if(i!=0) 
     { 
      while(Arrays.asList(no).contains(i1)) 
      { 
       r = new Random(); 
       i1 = r.nextInt(25 - 1) + 1; 
      } 
      no[i]= i1 ; 
     } 
     else 
     { 
      no[i]= i1 ; 
     } 
    } 

public void click_fun(FrameLayout arg0, TextView arg1, int n) 
{ 
if(counter<2) 
{ 
    arg0.setAnimation(an1); 
    if(no[n]<=12) 
    { 
     arg1.setText(""+no[n]); 
     arg0.setBackgroundResource(android.R.color.white); 
    } 
    else 
    { 
     arg1.setText(""+(no[n]-12)); 
     arg0.setBackgroundResource(android.R.color.white); 
    } 
    arg0.setTag(no[n]); 
    count[counter] = arg0; 
    counter++; 
    Log.i("animate", "anim2"); 
} 
else 
{ 
    Log.i("animate", "animo1"); 
    arg0.setAnimation(an1); 
    if(no[n]<=12) 
    { 
     arg1.setText(""+no[n]); 
     arg0.setBackgroundResource(android.R.color.white); 
    } 
    else 
    { 
     arg1.setText(""+(no[n]-12)); 
     arg0.setBackgroundResource(android.R.color.white); 
    } 
    arg0.setTag(no[n]); 
    count[counter] = arg0; 
    counter++; 
    Log.i("animate", "animo2"); 
    Uri uri = Uri.parse("android.resource://com.game/drawable/ic_launcher"); 
    int temp1 = (Integer) count[1].getTag(); 
    int temp2 = (Integer) arg0.getTag(); 
    Log.i("animate", "animo3"); 
    if((temp1-temp2)==-12 || temp1-temp2==12) 
    { 
     rem[1]=count[1]; 
     rem[2]=count[2]; 
     s_c=true; 
     score=score+10; 
     score_lbl.setText("Score : "+score); 
     score=score+10; 
     score_lbl.setText("Score : "+score); 
     level_counter=level_counter-2; 
    } 
    else 
    { 
     rev_count++; 
     revise[rev_count]=count[1]; 
     rev_count++; 
     revise[rev_count]=count[2]; 
     r_c=true; 
     score=score-2; 
     score_lbl.setText("Score : "+score); 
    } 
    counter=1; 
} 

}

Answer 1

我不認爲我完全理解你的處境。 1.創建字符串資源的數組：

private Integer[] Strings = { many, strings, R.string.stringa }; 

2.調用得到一個隨機資源的方法：

getRandomString(int); 

3.返回一個隨機字符串：

private String getRandomString(int random) 
    return getString(Strings[ random ]);