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SQL表:
用戶= ID,姓名,電子郵件..
英雄= ID,姓名,級別..
所有者=用戶ID,heroidSQL - 如何在另一個表中使用選定的ID?
我有兩個疑問:
$result = mysql_query("SELECT heroid FROM owner WHERE userid='$id'");
$heroid=mysql_fetch_row($result);
$result2 = mysql_query("SELECT name FROM hero WHERE ID = 'heroid[0]'");
$heroname = mysql_fetch_row($result2);
echo "User $id has a character named $heroname[0]";
$heroname = mysql_fetch_row($result2);
echo "User $id has a character named $heroname[0]";
..
這可以通過單個查詢來完成嗎?
啊,太棒了!謝謝 – Sindorej